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Setler [38]
2 years ago
5

Item 1

Mathematics
1 answer:
victus00 [196]2 years ago
3 0

Step-by-step explanation:

the sign - "<" correctly compares this ( -35__-23).

hope this helps you.

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What is the equation of a circle with center of (4,2) passing through the point (7,2)
attashe74 [19]

Answer:

(x-4)^2 + (y-2)^2 = 3^2

or

(x-4)^2 + (y-2)^2 = 9 (simplified if needed)

Step-by-step explanation:

-Equation of a circle is:

(x-h)^2+(y-k)^2=r^2 where the center is (h, k) and the radius is r^2.

-Place the center and the point onto that equation:

(7-4)^2+(2-2)^2=r^2

-Then, you solve:

(7-4)^2+(2-2)^2=r^2

(3)^2+(0)^2=r^2

9 +0=r^2

9=r^2

\sqrt{9} =\sqrt{r^2}

3=r

-So, the result is:

(x-4)^2+(y-2)^2=3^2

or

(x-4)^2+(y-2)^2=9 (simplified if needed)

3 0
3 years ago
Given the function f(x) = 5^x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3. Part A: Find the average r
Wewaii [24]
Table of the graph:
x: <em></em>1  2    3 
y: 5  25  125

Average Rate of Change = \frac{y_{2}-y_{1} }{x_{2} -  x_{1} }

Section A = 25-5/2-1 =20/1 =20
Section B = 125 - 25/ 3-2 = 100/1 = 100

So, Section B is 5 times greater than A.
Section B is greater because the slope of two points is greater than points in Section A.
8 0
3 years ago
Which is greater, 4.87 x 10^9 or 9.212 x 10^8? <br> please helpp
STatiana [176]

Answer: 4.87 x 10^9  is greater than 9.212 *10^8

Step-by-step explanation:

4.87 x 10^9  is greater than 9.212 *10^8 because it has the greater exponent.

4.87 * 10^9 =  4,870,000,000

9.212 *10^8= 921,200,000

4,870,000,000 > 921,200,000

6 0
3 years ago
X^2 + 4x + 4 = 0<br>please help!! I missed class! show steps!​
Stels [109]

Answer:

x= -2

Step-by-step explanation:

Step 1. In order to find the zeros of the function, we must factor it.

Step 2. To factor this, we have to find  two numbers that multiply to 4 and add to 4 which is 2 ( 2*2=4 and 2+2=4)

step 3. 0=(x+2)(x+2)

Step 4 make (x+2) equal to zero and solve which gives us -2, so -2 =x.

7 0
3 years ago
identify the postulate or theorem that proves the triangles congruent. AAS, SAA, ASA, The triangles cannot be proven congruent
nirvana33 [79]
AAS and SAA don't prove congruence. 
You can have two triangles that have AAS or SAA and are not congruent.

From this picture, these triangles are congruent by ASA .
4 0
3 years ago
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