91284 the nearest ten thousand

Mathematics

2 answers:

almond37 [142]3 years ago

8 0

91284 the nearest ten thousand is 9

Phantasy [73]3 years ago

6 0

91284 rounded to the nearest ten thousand is 91, 000
Its more closer to 91,000 then 92,000

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on patrick's test he got 14 multiple choice questions and 6 true or false questions correct. patrick also got 1 multiple choice

solniwko [45]

So first add the multiple choice together to get 15 and the true/false together to get 10. Then add those together to get 25. Since there was 15 multiple choice, divide 15 by 25 to get 3/5. This is .8 in decimal form and to convert it to a percent multiply it by 100 to get 80%. Hope this helps!

8 0

3 years ago

How many quarts does it take to fill a kitchen sink

Anna [14]

The average kitchen sink has a width of approximately 23.5 inches, a length of approximately 31.5 inches, and a depth of approximately 21 inches.

Multiplying these values together, we can see that the volume of the average kitchen sink is about 15545.25 cubic inches.

The conversion of cubic inches to liquid gallons is 1 cubic inch = approximately 0.004329 gallons.

Multiplying these numbers, we can see that 15545.25 cubic inches is the same as approximately 67.29538725 gallons. Now, we just have to multiply that number by 4, since there are 4 quarts in a gallon.

67.29538725 * 4 = 269.181549

It takes approximately 269.181549 quarts to fill the average kitchen sink.
Hope that helped =)

3 0

3 years ago

Yea I can do tomorrow it would take me to get the money back to you

Tems11 [23]

Given, the equation that represents the height of an object:

$y(t)=100t-16t^2$

First, we will find the velocity of the object which is the first derivative of the height using the method of the limits

$\frac{dy}{dt}=\lim_{h\to a}\frac{y(3+h)-y(3)}{(3+h)-(3)}$

We will find the value of the function y(t) when t = 3, and when t = 3+h

$\begin{gathered} y(3+h)=100(3+h)-16(3+h)^2 \\ y(3+h)=300+300h-16(9+6h+h^2) \\ y(3+h)=300+300h-144-96h-16h^2 \\ y(3+h)=156+4h-16h^2 \\ y(3)=100(3)-16(3)^2=156 \end{gathered}$

Substitute y(3+h) and y(3) into the expression of the limit

$\begin{gathered} \frac{dy}{dt}|_{t=3}=\lim_{h\to a}\frac{156+4h-16h^2-156}{3+h-3}=\lim_{h\to a}\frac{4h-16h^2}{h} \\ \\ \frac{dy}{dt}|_{t=3}=\lim_{h\to a}(4-16h) \end{gathered}$

Where a = 0

d) compute the instantaneous velocity at t = 3