Answer:
3480
Step-by-step explanation:
Set it up so it looks like this.
(2580 + 2930 + x )/3 = 3000 Combine the terms on the left
(5510 + x) / 3 = 3000 Multiply by 3
5510 + x = 9000 Subtract 5510
x = 9000 - 5510
x = 3490
Does that really work?
2580 + 2930 + 3490 = 9000
Which says it does work.
Answer:
8748
Step-by-step explanation:
a^5b^-6
when replacing the variables with their values :
3^5 -6^2
3^5 = 3*3*3*3*3 = 243
(-6)^ 2 = 36
243 * 36 =
8748
D. You start out with $500, it does not use a variable, knocking out a and b. Also, you need at least the needed amount of money, so b or c cannot be the answer. This only leaves d.
Answer:
9
Step-by-step explanation:
when you subtract a negative, you are basically adding. 2+7=9
There are two unknowns in this problem. To start, let's assign variables to each of them. Let x be the age of Jacob and y be the age of Isaiah. Then, we formulate equations based on the relationships stated.
x = 7 + y --> eqn 1
x + y = 63 --> eqn 2
Substituting eqn 1 to eqn 2, then solve for x and y:
(7+y)+y = 63
7 + 2y = 63
2y = 63 - 7
2y = 56
y = 56/2
y = 28
x = 28 + 7 = 35
Therefore, Jacob is 35 years old, and Isaiah is 28 years old.
