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ozzi
3 years ago
15

Choose the characteristics that you think are important for scientists to have. Check all that apply. antisocial, boring, close-

minded, creative, curious, honest, skeptical
Chemistry
2 answers:
liraira [26]3 years ago
7 0

For a scientist it is important to be creative, curious, honest and skeptical.

A scientist is someone who gives a valid answer of the question. He uses various types of scientific knowledge to answer the question in a practical way.

A scientist should be honest about his work and tasks that he is performing.

He must be curious to know everything about his work.

He should be creative about what is he doing and should not jump to a conclusion without observing and experimenting on it.


solniwko [45]3 years ago
6 0

Answer: creative, curious, honest, skeptical

A scientist is a professional, who tries to find out the reasons behind natural phenomenas by constructing a suitable research plan. The following are the characteristics that scientists should have:

1. Creative: Scientists should be creative, which means they should have ability to modify previous theories and laws.

2. Curious: Scientists should be creative, which means they should have interest in knowing the facts related to different natural phenomenas.

3. Honest: Scientists should be honests, they should not repeat the findings of their fellows or competents. They should atleast provide a review of their scientific work. The notion of the reserach should be to serve the human society.

4. Skeptical: Scientists should be skeptical, which means the tendency of doubt should occur during the tenure of research. The skepticism will lead to many trials in an experiment, until a more accurate result is obtained.


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Answer:

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4 0
2 years ago
A balloon occupies a volume of 2.00 l at 40.0oc. how much volume will it occupy at 30.0oc?
hodyreva [135]
<span>Charles' law says "at a constant pressure, the volume of a fixed amount of gas is directly proportional to its absolute temperature".

V </span>α T

Where V is the volume and T is the temperature in Kelvin of the gas. We can use this for two situations as,
V₁/T₁ = V₂/T₂

V₁ = 2.00 L
T₁ = 40.0 ⁰C = 313 K
V₂ = ?
T₂ = 30.0 ⁰C = 303 K

By applying the formula,
2.00 L / 313 K = V₂ / 303 K                   
                   V₂ = (2.00 L / 313 K) x 303 K
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7 0
3 years ago
A Silty Clay (CL) sample was extruded from a 6-inch long tube with a diameter of 2.83 inches and weighed 1.71 lbs. (a) Calculate
inna [77]

Answer:

a) the wet density of the CL sample is 0.0453 lb/in³

b) the water content in the sample is 65.37%

c) the dry density of the CL sample is 0.0274 lb/in³

Explanation:

Given that;

diameter d = 2.83 in

length L = 6 in

weight m = 1.71 lbs

A piece of clay sample had wet-weight of 140.9 grams  and dry-weight of 85.2 grams

a) wet density of the CL sample

wet density can be expressed as  p = M /v

V is volume of sample which is; π/4×d²×L

so p = M / π/4×d²×L

we substitute

p = 1.71 / (π/4 × (2.83)²× 6

p = 1.71 / 37.741

p = 0.0453 lbs/in³

so the wet density of the CL sample is 0.0453 lb/in³

b)

water content of sample is taken as;

w =  (wet_weight - dry_weight) / dry_weight

we substitute

w = (140.9 - 85.2) / 85.2

w = 55.7 / 85.2

w = 0.6537 = 65.37%

therefore the water content in the sample is 65.37%

c)

dry density of the CL sample

to determine the dry density, we say;

Sd = p / ( 1 + w )

we substitute

Sd = 0.0453 / ( 1 + 0.6537)

Sd = 0.0453 /  1.6537

Sd = 0.0274 lb/in³

therefore the dry density of the CL sample is 0.0274 lb/in³

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