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iVinArrow [24]
3 years ago
6

Will mark brainlist need help

Chemistry
1 answer:
Stella [2.4K]3 years ago
4 0

Answer:

0.219 mol HCI

Explanation:

Iron(II) sulfide reacts with hydrochloric acid according to the reaction:

FeS (s) + 2HCl (aq) → FeCl2 (s) + H2S (g)

A reaction mixture initially contains 0.223 mol FeS and 0.665 mol HCl.

Once the reaction has occurred as completely as possible, what amount (in moles) of the excess reactant remains?

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what do the symbols tell you about the conditions of the reaction shown to the right check all boxes that apply
alukav5142 [94]

Answer:

Sorry but erm was their supposed to be a image attach with it

Explanation:

6 0
3 years ago
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What is N? (Needed electrons)
lianna [129]
Do you know what is meant by needed? does it mean lone pairs?
8 0
3 years ago
Help please I need help with these two questions answer truthfully get brainliest?!!​
irina1246 [14]

Answer:

1. 3x-3=18

Value of x=7

2. 4x-5=23

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2 years ago
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Solution A is 0.44 M and reacts with 0.11 M of solution B. Assume that the value of x is 0, the value of y is 1, and r is 1.07 ×
xz_007 [3.2K]

Answer:

K, the rate constant = 9.73 × 10^(-1)/s

Explanation:

r = K × [A]^x × [B]^y

r = Rate = 1.07 × 10^(-1)/s

K = Rate constant

A and B = Concentration in mol/dm^-3

A = 0.44M

B = 0.11M

x = Order of reaction with respect to A = 0

y = Order of reaction with respect to B = 1

Solving, we get

r/([A]^x × [B]^y) = K

K = 1.07 × 10^(-1)/s/(0.44^0 × 0.11^1)= 0.9727

K = 0.9727

7 0
3 years ago
The amount of radioactive carbon-14 in a sample is measured using a Geiger counter, which records each disintegration of an atom
sergij07 [2.7K]

Answer:

4121 years

Explanation:

From;

0.693/t1/2 = 2.303/t log No/N

t1/2= half life of the carbon-14

No= count rate of the living tissue

N= count rate of the sample

t = age of the sample

0.693/5730 =2.303/t log (13.5/8.2)

1.21 * 10^-4 = 2.303/t * 0.2165

1.21 * 10^-4 = 0.4986/t

t = 0.4986/1.21 * 10^-4

t = 4121 years

7 0
3 years ago
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