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mrs_skeptik [129]
3 years ago
12

How are chemical bonds important in metabolism?

Chemistry
1 answer:
mixas84 [53]3 years ago
8 0
Chemical bonds are broken to supply us with energy. Without bonds, and our ability to break them, the food we eat would not supply us with energy.
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What attractive force draws in surrounding electrons for chemical bonds?
Dmitrij [34]

The formation of chemical bonds occurs due to the attractive forces between oppositely charged ions (ionic bonds) or by sharing of electrons (covalent bonds).

An atom having tendency of attracting a shared pair of electrons towards itself and this chemical property is said to Electronegativity .

Thus, the attractive forces which draws in surrounding electrons for chemical bonds is electronegativity.

3 0
4 years ago
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Which is bigger in width mm,cm,m,km
Kay [80]
Km is the biggest measure in width (even if there are bigger measures like Mm, Gm, Tm).

1 Km = 1000 m, 100000 cm and 1000000 mm
4 0
3 years ago
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(Please Help!) Aluminum reacts with oxygen to produce aluminum oxide (AI203). The balanced chemical equation for this reaction i
andriy [413]

#1

Moles of Oxygen =3

Molecules:-

  • 3×Avagadro no
  • 3(6.022×10²³)
  • 18.066×10²³
  • 1.8066×10²²molecules

#2

Its because according to law of conservation of mass- Mass is neither created nor destroyed

AS ITS BALANCED SO BOTH SIDES ARE SAME .

HENCE THEY OBEY

5 0
2 years ago
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A gas has a volume of 1.75L at -23°C and 150.0 kPa. At what temperature would the gas occupy 1.30L at 210.0 kPa?
Nastasia [14]

Answer:

At -13 ^{0}\textrm{C} , the gas would occupy 1.30L at 210.0 kPa.

Explanation:

Let's assume the gas behaves ideally.

As amount of gas remains constant in both state therefore in accordance with combined gas law for an ideal gas-

                                          \frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}

where P_{1} and P_{2} are initial and final pressure respectively.

           V_{1}  and V_{2} are initial and final volume respectively.

           T_{1} and T_{2} are initial and final temperature in kelvin scale respectively.

Here P_{1}=150.0kPa , V_{1}=1.75L , T_{1}=(273-23)K=250K, P_{2}=210.0kPa and V_{2}=1.30L

Hence    T_{2}=\frac{P_{2}V_{2}T_{1}}{P_{1}V_{1}}

            \Rightarrow T_{2}=\frac{(210.0kPa)\times (1.30L)\times (250K)}{(150.0kPa)\times (1.75L)}

            \Rightarrow T_{2}=260K

            \Rightarrow T_{2}=(260-273)^{0}\textrm{C}=-13^{0}\textrm{C}

So at -13 ^{0}\textrm{C} , the gas would occupy 1.30L at 210.0 kPa.

5 0
3 years ago
Identify the elements that are found as liquids at room temperature. What is the state of matter of the majority of the elements
N76 [4]


Mercury (Metal) is in liquid form at room temperature
Bromine (Non-Metal) is in liquid form at room temperature

Most of the elements are solid, 11 gases and 6 liquids
3 0
2 years ago
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