1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ivahew [28]
4 years ago
11

High-level radioactive waste requires deep burial because it is explosive. TRUE FALSE

Chemistry
2 answers:
Norma-Jean [14]4 years ago
8 0
True.................
Juli2301 [7.4K]4 years ago
6 0
Tge radioactive wast requires deep burial because it is an explosive false because of the burial it wont explose
You might be interested in
A gallon of paint covers 350 square feet.
trapecia [35]

Answer:

2,137... gallons

Explanation:

(160+140+14x16x2)/350=2,137...

4 0
2 years ago
Hydrazine, , emits a large quantity of energy when it reacts with oxygen, which has led to hydrazine used as a fuel for rockets:
Tcecarenko [31]

Answer:

1.25~mol~H_2O and 0.627~mol~N_2

Explanation:

Our goal for this question is the calculation of the number of moles of the molecules produced by the reaction of hydrazine (N_2H_4) and <u>oxygen</u> (O_2). So, we can start with the <u>reaction</u> between these compounds:

N_2H_4~+~O_2~->~N_2~+~H_2O

Now we can <u>balance the reaction</u>:

N_2H_4~+~O_2~->~N_2~+~2H_2O

In the problem, we have the values for both reagents. Therefore we have to <u>calculate the limiting reagent</u>. Our first step, is to calculate the moles of each compound using the <u>molar masses values</u> (32.04 g/mol for N_2H_4 and 31.99 g/mol for O_2):

20.1~g~N_2H_4\frac{1~mol~N_2H_4}{32.04~g~N_2H_4}=0.627~mol~N_2H_4

20.1~g~O_2\frac{1~mol~O_2}{31.99~g~O_2}=0.628~mol~O_2

In the balanced reaction we have 1 mol for each reagent (the numbers in front of O_2 and N_2H_4 are 1). Therefore the <u>smallest value would be the limiting reagent</u>, in this case, the limiting reagent is N_2H_4.

With this in mind, we can calculate the number of moles for each product. In the case of N_2 we have a <u>1:1 molar ratio</u> (1 mol of N_2 is produced by 1 mol of N_2H_4), so:

0.627~mol~N_2H_4\frac{1~mol~N_2}{1~mol~N_2H_4}=~0.627~mol~N_2

We can follow the same logic for the other compound. In the case of H_2O we have a <u>1:2 molar ratio</u> (2 mol of H_2O is produced by 1 mol of N_2H_4), so:

0.627~mol~N_2H_4\frac{2~mol~H_2O}{1~mol~N_2H_4}=~1.25~mol~H_2O

I hope it helps!

4 0
4 years ago
Which of the following methods will usually cause a reaction to speed up? Combining the reactants at a lower temperature. Reduci
Aneli [31]
Ans: grinding one of the reactants into a powder.

this increases the surface area and hence there would be more chances of collisions happening. therefore reaction rate would increase
6 0
4 years ago
Read 2 more answers
What air pressure would be needed for water to boil at 80°C
True [87]
47 Kpa would bw the pressure needes
3 0
3 years ago
Read 2 more answers
How many ions of aluminum oxide (Al²O³) are there in 200 g of Al²O³??<br><br>​
valentinak56 [21]

= 6.022 × 1020

Explanation<em>;</em>

Mole of aluminium oxide (Al2O3) is

⇒ 2 x 27 + 3 x 16

Mole of aluminium oxide = 102 g

i.e., 102 g of Al2O3= 6.022 x 1023 molecules of Al2O3

Then, 0.051 g of Al2O3 contains = 6.022 x 1023 / (102 x 0.051 molecules)

= 3.011 x 1020 molecules of Al2O3

The number of aluminium ions (Al3+) present in one molecule of aluminium oxide is 2.

Therefore, the number of aluminium ions (Al3+) present in 3.11 × 1020 molecules (0.051g) of aluminium oxide (Al2O3)

= 2 × 3.011 × 1020

=<em> 6.022 × 1020</em>

<em>hope </em><em>it </em><em>helps</em><em>_</em>

6 0
2 years ago
Other questions:
  • HELP ASAP PLEASE!!!!
    15·1 answer
  • Complete the table to summarize the properties of the different subatomic particles
    10·2 answers
  • The rate consnt for a reaction is measured as a function of temperature. A plot of ln k versus 1/T is linear and has s slope of
    15·1 answer
  • Type in he correct values to correctly represent the valence electron configuration of oxygen
    6·1 answer
  • 4. Change the following in to chemical equations and balance them.
    6·1 answer
  • PLEASE HELP!<br><br> what are the steps that occur during the combustion of hydrogen?
    14·1 answer
  • Nate and Clara are drawing pictures with markers. There are 8 markers in a set. Nate has 9 markers and Clara has 7. What can Nat
    8·2 answers
  • What are the lessons that you learn from nature​
    15·2 answers
  • How do you know your cell's are working
    14·2 answers
  • for a theoretical yield of 22 g and actual yield of 13 g, calculate the percent yield for a chemical reaction
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!