In the given system, A is the central atom which is surrounded by four B atoms and forms 4 covalent bonds. Ideally, this structure could correspond to a square planar molecular geometry. However, there are two lone pairs of electrons on the central atom A which must be considered in order interpret the electron geometry.
Thus the electron domain geometry around A is octahedral
Answer:
The molarity of acid is 3 M.
Explanation:
Given data:
Volume of H₃PO₄ = 25 mL
Volume of NaOH = 50 mL
Molarity of NaOH = 1.50 M
Molarity of H₃PO₄ = ?
Solution:
Formula:
M₁V₁ = M₂V₂
M₁ = M₂V₂ / V₁
M₁ = 1.50 M ×50 mL / 25 mL
M₁ = 75 M. mL / 25 mL
M₁ = 3 M
The molarity of acid is 3 M.
Answer: 
Explanation:
cM 0 0
So dissociation constant will be:
Given: c = 0.15 M
pH = 1.86
= ?
Putting in the values we get:
Also ![pH=-log[H^+]](https://tex.z-dn.net/?f=pH%3D-log%5BH%5E%2B%5D)
![1.86=-log[H^+]](https://tex.z-dn.net/?f=1.86%3D-log%5BH%5E%2B%5D)
![[H^+]=0.01](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D0.01)
![[H^+]=c\times \alpha](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3Dc%5Ctimes%20%5Calpha)
As ![[H^+]=[ClCH_2COO^-]=0.01](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D%5BClCH_2COO%5E-%5D%3D0.01)
![K_a=1.67\times 10^{-3]](https://tex.z-dn.net/?f=K_a%3D1.67%5Ctimes%2010%5E%7B-3%5D)
Thus the vale of for the acid is
The nuclear equation for
formation of iron-54 through fusion would be Fe + heat ----> Fe_54 + +
neutrons. I am hoping that this answer has satisfied your query
about and it will be able to help you, and if you’d like, feel free to ask
another question.
400ml my dude is the wrong answer
