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N76 [4]
3 years ago
8

Molecular formula of a compound with an empirical formula c5h6 and a molar mass of 132.21

Chemistry
1 answer:
melisa1 [442]3 years ago
6 0

Answer:C10H12

Explanation:

Given :empirical formula =C5H6

molar mass of carbon =12 g /mole approximately

molar mass of hydrogen =1.01g/mole approximately

molar mass of C5H6=(5*12)+(6*1.01)=66.06 g/moles

132.21/66.06=2 approximately

therefore ,the answer is  C10H12

I HOPE IT HELPS !!

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3 years ago
Which element will be more reactive - Mg (magnesium) OR Se (Selenium)? *
anygoal [31]

Answer:

magnesium

Explanation:

magnesium is in Group 2, in the periodic table. this means that it has 2 valence electrons. the less valence electrons an element or atom has, the more reactive. Selenium has 6 valence electrons. as a result, Mg is more reactive

5 0
3 years ago
PROBLEMS
AlekseyPX

Answer:

1.) 0.1 M

2.) 0.2 M

3.) 1 M

4.) Solution #3 is the most concentrated because it has the highest molarity. This solution has the largest solute to solvent ratio. The more solvent there is, the lower the concentration and molarity.

Explanation:

To find the molarity, you need to (1) convert grams NaOH to moles (via molar mass from periodic table) and then (2) calculate the molarity (via the molarity equation). All of the answers should have 1 sig fig to match the given values.

Molar Mass (NaOH): 22.99 g/mol + 16.00 g/mol + 1.008 g/mol

Molar Mass (NaOH): 39.998 g/mol

4 grams NaOH           1 mole
----------------------  x  ------------------  = 0.1 moles NaOH
                                 39.998 g

1.)

Molarity = moles / volume (L)

Molarity = (0.1 moles) / (1 L)

Molarity = 0.1 M

2.)

Molarity = moles / volume (L)

Molarity = (0.1 moles) / (0.5 L)

Molarity = 0.2 M

3.)

Molarity = moles / volume (L)

Molarity = (0.1 moles) / (0.1 L)

Molarity = 1 M

7 0
2 years ago
A reaction mechanism has the following elementary step as the slow step: B2A What is the rate law for this elementary step? O ra
xenn [34]

Answer:

r = k [ B ]

Explanation:

  • B → 2A

⇒ r = k [ A ]/2 = k [ B ]

3 0
3 years ago
A sample of CO2 weighing 86.34g contains how many molecules?
irakobra [83]

Answer:

1.181 × 10²⁴ molecules CO₂

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

86.34 g CO₂

<u>Step 2: Identify Conversion</u>

Avogadro's Number

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Convert</u>

<u />86.34 \ g \ CO_2(\frac{1 \ mol \ CO_2}{44.01 \ g \ CO_2} )(\frac{6.022 \cdot 10^{23} \ molecules \ CO_2}{1 \ mol \ CO_2} ) = 1.18141 × 10²⁴ molecules CO₂

<u>Step 4: Check</u>

<em>We are given 4 sig figs. Follow sig fig rules and round.</em>

1.18141 × 10²⁴ molecules CO₂ ≈ 1.181 × 10²⁴ molecules CO₂

4 0
3 years ago
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