Molecular formula of a compound with an empirical formula c5h6 and a molar mass of 132.21
1 answer:
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Answer:
1) 1.202 L
, 2) 1.291 dg
, 3) 204.877 and 4) 1.04x
Explanation:
You need to review about conversion factors and how to use them in the correct order. You can cancel the units and get the ones that you need if you use the appropriate conversion factors, remember is a number that you can use to multiply or divide.
For your exercise:
1) The conversion factor is: 1 L = 1000 mL
You will need to divide by 1000 mL to obtain liters L
1202.57120 mL x = 1.202 L
2) The conversion factor is: 1 g = 10 dg
0.1290743 g x = 1.291 dg
For the next exercises, you need to follow some rules:
1. All numbers that are different from Zero (non-zero digits) are significant figures.
2.The Zeros between non-zeros digits (Imbedded zeros) always are significant, 2007.
3. If you want to be specific and want some zeros to be significant you need to add a decimal point. For example 500. or 500.0
4. Leading zeros (to the left) are not significant.
5. Trailing zeros (zeros to the right) in a whole number without decimal point are not significant.
3) 843.062 - 638.1848 = 204.8772
Now if we round to 6 significant figures we get 204.877
4)123.0 x 8.43 = 1036.89
Now we round to 3 significant figures because 8.43 has the least significant figures.
1.04x