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STALIN [3.7K]
3 years ago
9

In the following reaction, eight moles of sodium hydroxide is broken down into four moles of sodium oxide and four moles of wate

r.
What is the percent error if your experiment yields 195 grams of sodium oxide?
2NaOH→Na2O+H2O
Chemistry
1 answer:
maxonik [38]3 years ago
8 0

Answer:

21.344%

Explanation:

For the given chemical reaction, 8 moles of the reactant should produce 4 moles of Na_{2}O. However, 195 g of Na_{2}O was produced instead. The molar mass of Na_{2}O is 61.9789 g/mol.

Thus, the moles of Na_{2}O produced = 195/61.9789 = 3.1462 moles

The percent error = [(Actual -Experiment)/Actual]*100%

The percent error =  [(4.00 - 3.1462)/4.00]*100% = (0.85376/4.00)*100% = 21.344%

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