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lina2011 [118]
3 years ago
11

An area of wave-washed sediment along a coast is called a __________.

Physics
2 answers:
iris [78.8K]3 years ago
6 0
Hello.

The answer is a beach.

<span>An area of wave-washed sediment along a coast is called a beach.

Have a nice day</span>
neonofarm [45]3 years ago
4 0

The correct answer is BEACH. I just finished the assignment and that's the correct answer.

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The temperature of a smelting furnace is found to be 2000 degree Celsius.find the temperature on Fahrenheit scale​
Dima020 [189]

Answer:

3632.

Explanation:

Based on the formula:

2000×(9/5)+32=3632

6 0
3 years ago
Are plants carnivores<br>Ture or False​
monitta

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False they are producers and they don' eat anything only produce and provide

Explanation:

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3 years ago
A ball is thrown into the air with a vertical velocity of 50 m/s and a horizontal
daser333 [38]

\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Projectile Motion.

Since, here given that, vertical velocity= 50m/s

we know that u*sin(theta) = vertical velocity

so the time taken to reach the maximum height or the time of Ascent is equal to

T = Usin(theta) ÷ g, here g = 9.8 m/s^2

so we get as,

T = 50/9.8

T = 5.10 seconds

thus the time taken to reach max height is 5.10 seconds.

5 0
3 years ago
Which process is responsible for changing the composition of rock?
Crazy boy [7]

Erosion, weathering, mechanical changes, chemical changes.

Really, any interaction can change the composition of a rock whether it be done by man or through nature.

4 0
3 years ago
Read 2 more answers
Over a short interval the coordinate of a car in the meters isgiven by x(t) = 27t - 4.0 t3 where time t is in seconds,at the end
wariber [46]

Answer:

5. -24 m/s²

Explanation:

Acceleration: This can be defined as the rate of change of velocity.

The S.I unit of acceleration is m/s².

mathematically,

a = dv/dt ............................ Equation 1

Where a = acceleration, dv/dt = is the differentiation of velocity with respect to time.

But

v = dx(t)/dt

Where,

x(t) = 27t-4.0t³...................... Equation 2

Therefore, differentiating equation 2 with respect to time.

v = dx(t)/dt = 27-12t²............. Equation 3.

Also differentiating equation 3 with respect to time,

a = dv/dt = -24t

a = -24t .................... Equation 4

from the question,

At the end of 1.0 s,

a = -24(1)

a = -24 m/s².

Thus the acceleration = -24 m/s²

The right option is 5. -24 m/s²

4 0
3 years ago
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