Explanation:
First of all we calculate the volume which is 20m×10m×8m= 1600m^3 and then multiply the density by the volume to get the mass which will equal to 99200kg therefore the weight will be
<em><u>Weight</u></em>
mass × acceleration due to gravity
=99200kg × 10m^s^2
=992000N
Answer:
The kinetic energy of the mass at the instant it passes back through the equilibrium position is 0.06500 J.
Explanation:
Given that,
Mass = 2.15 kg
Distance = 0.0895 m
Amplitude = 0.0235 m
We need to calculate the spring constant
Using newton's second law
Where, f = restoring force
Put the value into the formula
We need to calculate the kinetic energy of the mass
Using formula of kinetic energy
Here,
Here,
Put the value into the formula
Hence, The kinetic energy of the mass at the instant it passes back through the equilibrium position is 0.06500 J.
Answer:
1.8m
Explanation:
Let the Elastics of the steel ASTM-36
The strain of the bar when subjected to 150 MPa is
Therefore, if the bar elongates by 1.35 mm, then the original length L would be:
or 1.8m
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