Ask question

Ask question

All categories

3 years ago

7

A box experiencing a gravitational force of 600 N is being pulled to the right with force of 250 N. A 25 N frictional force acts

on the box as it moves to the right.

1 answer:

bearhunter [10]3 years ago

6 0

Answer: 0 NEWTONS

Explanation:

You might be interested in

Define velocity is the question

Oxana [17]

Answer:

The velocity of an object is the rate of change of its position with respect to a frame of reference, and is a function of time. Velocity is equivalent to a specification of an object's speed and direction of motion (e.g. 60 km/h to the north).

Explanation:

4 0

3 years ago

Read 2 more answers

How does sound intensity differ from loudness?

Artyom0805 [142]

Answer:

Sound intensity is the amount of energy carried by sound versus loudness is a subjective measurement of the audible sound.

Sound intensity is measured in watt per square meter where loudness is measured in sones (sone is a subjective measurement and not an SI unit)

6 0

3 years ago

mass of the planet is 12 times that of earth and its radius is thrice that of earth , then find the escape velocity on that plan

Over [174]

Answer:

The escape velocity on the planet is approximately 178.976 km/s

Explanation:

The escape velocity for Earth is therefore given as follows

The formula for escape velocity, $v_e$ , for the planet is $v_e = \sqrt{\dfrac{2 \cdot G \cdot m}{r} }$

Where;

$v_e$ = The escape velocity on the planet

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

m = The mass of the planet = 12 × The mass of Earth, $M_E$

r = The radius of the planet = 3 × The radius of Earth, $R_E$

The escape velocity for Earth, $v_e_E$ , is therefore given as follows;

$v_e_E = \sqrt{\dfrac{2 \cdot G \cdot M_E}{R_E} }$

$\therefore v_e = \sqrt{\dfrac{2 \times G \times 12 \times M}{3 \times R} } = \sqrt{\dfrac{2 \times G \times 4 \times M}{R} } = 16 \times \sqrt{\dfrac{2 \times G \times M}{R} } = 16 \times v_e_E$

$v_e$ = 16 × $v_e_E$

Given that the escape velocity for Earth, $v_e_E$ ≈ 11,186 m/s, we have;

The escape velocity on the planet = $v_e$ ≈ 16 × 11,186 ≈ 178976 m/s ≈ 178.976 km/s.

3 0

3 years ago

Give examples of factors or criteria often used to determine higher wages for a particular job

marshall27 [118]

-- the applicant's previous experience at similar jobs;
-- the color of the applicant's hair;
-- the applicant's grammar and vocabulary;
-- where the applicant went to school;
-- the shirt the applicant wears to the job interview;
-- the applicant's favorite football team;
-- the applicant's self-confidence;

5 0

3 years ago

Read 2 more answers

What is the weight of a feather (mass = 0.0001 kg) that floats through earth's and the moon's atmospheres?

Dvinal [7]

Weight = (mass) x (acceleration of gravity)

Acceleration of gravity = 9.81 m/s² on Earth, 1.62 m/s² on the Moon.

The feather's weight is . . .

On Earth: (0.0001 kg) x (9.81 m/s²) = <em>0.000981 Newton </em>

On the Moon: (0.0001 kg) x (1.62 m/s²) = <em>0.000162 N</em>

The presence or absence of atmosphere makes no difference. In fact, the numbers would be the same if the feather were sealed in a jar, or spinning wildly in a tornado, or hanging by a thread, or floating in a bowl of water or chicken soup. Weight is just the force of gravity between the feather and the Earth. It's not affected by what's around the feather, or what's happening to it.

6 0

3 years ago