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3 years ago

Please help extremely important!

Physics

1 answer:

Nikolay [14]3 years ago

4 0

Answer:

the awnser is A

Explanation:

the awnser is A

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Dario, a prep cook at an Italian restaurant, spins a salad spinner and observes that it rotates 20.0 times in 5.00 seconds and t

ziro4ka [17]

Answer:

(a). The acceleration is 8.3 rad/s².

(b). The time is 3.0 sec.

Explanation:

Given that,

Rotation = 20.0 times

Time = 5.00 sec

We need to calculate the angular frequency

Using formula of angular frequency

$\omega_{i}=20\times\dfrac{2\pi}{T}$

put the value into the formula

$\omega_{i}=20\times\dfrac{2\pi}{5.00}$

$\omega_{i}=8.00\pi$

We need to calculate the angular displacement

Using formula of angular displacement

$\theta=6\times2\pi=12\pi$

We need to calculate the angular acceleration

Using equation of angular motion

$\omega_{f}^2-\omega_{i}^2=2\alpha\times\theta$

$0-64\pi^2=2\times12\pi\times\alpha$

$\alpha=-\dfrac{64\pi^2}{24\pi}$

$\alpha=-8.3\ rad/s^2$

Negative sign shows the opposite direction of the motion.

The acceleration is 8.3 rad/s².

We need to calculate the time

Using equation of angular motion

$\omega_{f}-\omega_{i}=\alpha\times t$

$0-8\pi=-8.3t$

$t=\dfrac{8\pi}{8.3}$

$t=3.0\ sec$

The time is 3.0 sec.

Hence, (a). The acceleration is 8.3 rad/s².

(b). The time is 3.0 sec.

4 0

3 years ago

Complete the following

Furkat [3]

answer is down hera

3 0

3 years ago

An object accelerates from 9 m/s to 26 m/s in 8 seconds. What is the acceleration? Round your answer to

qwelly [4]

Explanation:

Acceleration is the change in velocity over time.

a = Δv / Δt

a = (26 m/s − 9 m/s) / 8 s

a ≈ 2.1 m/s²

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3 years ago

Read 2 more answers

(physical science) could someone please help me out with this lab? if i’m being honest i did the lab but i lost all of my work :

djverab [1.8K]

Explanation:

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6 0

3 years ago

Select the correct answer.

Nastasia [14]

The force of a test charge would be doubled if the electric field is doubled.

Answer: Option A

<u>Explanation:</u>

Electric field is the region or range up to which a charge particle will have its influence of electric energy on another charged particles. So the experienced force by the test charge up to a certain range is defined as the electric field of that charged particle.

This means that the electric field strength is inversely proportionate to the test charge and directly proportionate to the force acting on the test charge. As ,

$E=\frac{\text { Force }}{\text { Test charge }}$

So, force will be product of electric field strength with test charge. Thus,

$\text { Force } \propto \text { Test charge and Force } \propto \text { Electric field }$

So, if there is increase in the electric field, then there will be increase in the force of the test charge. Thus, if the electric field is doubled thereby the force of a test charge will also be doubled.

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4 years ago