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Katen [24]
3 years ago
6

What is the displacement of a spring if it has a spring constant of 10 N/m, and a force of 2.5 N is applied?

Physics
2 answers:
pochemuha3 years ago
5 0
O.25 m is the displacement
disa [49]3 years ago
4 0

Answer:

Displacement, x = 0.25 m

Explanation:

It is given that,

Spring constant, k = 10 N/m

Force, F = 2.5 N

We have to find the displacement of a spring. It can be calculated using Hooke's law i.e.

F = - kx

x=\dfrac{F}{k}

x=\dfrac{2.5\ N}{10\ N/m}

x = 0.25 m

Hence, the displacement of the spring is 0.25 m.

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A .2kg Basketball is pitched with a velocity or 40 m/s and then bed and into the picture with a velocity of 60 m/s. What is the
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Answer:

40kgm

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The kinetic energy of a moving object is E=12mv2. A 61 kg runner is moving at 10kmh. However, her speedometer is only accurate t
jek_recluse [69]

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e=3367.2J

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Since the speedometer is only accurate to within 0.1km/h the experimental speed is

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Knowing that we can calculate Kinetic energy for the real and experimental speed

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E_{e}=\frac{1}{2}mv^2=\frac{1}{2}(61000g)(2.75m/s)^2=230656J

Now, the potential error in her calculated kinetic energy is:

e=E_{r}-E_{e}=(234023-230656)J=3367.2J

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4 0
4 years ago
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VikaD [51]

5.5 s

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The time it takes for the ball to reach its maximum height can be calculated using

v_y = v_{0y} - gt \Rightarrow t = \dfrac{v_{0y}}{g}

since v_y = 0 at the top of its trajectory. Plugging in the numbers,

t = \dfrac{(54\:\text{m/s})}{(9.8\:\text{m/s}^2)} = 5.5\:\text{s}

8 0
3 years ago
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