In a batch of 960 calculators, 8 were found to be defective. What is the probability that a calculator chosen at random will be
defective? Write the probability as a percent. Round to the nearest tenth of a percent if necessary
2 answers:
Answer: 0.8%
Step-by-step explanation:
Given : In a batch of 960 calculators, 8 were found to be defective.
i.e. Total calculators =960
Number of defective calculator = 8
We know that the probability of any event is given by :-

In percent, ![0.00833333333333\times100=0.833333333333\%\\\\\approx0.8\%\ \ \ [\text{Rounding to the nearest tenth.}]](https://tex.z-dn.net/?f=0.00833333333333%5Ctimes100%3D0.833333333333%5C%25%5C%5C%5C%5C%5Capprox0.8%5C%25%5C%20%5C%20%5C%20%5B%5Ctext%7BRounding%20to%20the%20nearest%20tenth.%7D%5D)
Hence, the probability that a calculator chosen at random will be defective=0.8%
This is a case of empirical (observed) probability. Historically speaking, 8 out of 960 calculators were found to be defective.
Thus P(defective calculator) = 8/960, or 0.008333 ...
As a percent, this is 0.8%.
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