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3 years ago

Olve the two-step equation and identify the steps. 2 = − 7 4 + 1 4 x

Mathematics

1 answer:

saul85 [17]3 years ago

6 0

Answer:

x = 5.142

Step-by-step explanation:

2=-74+14x

if you want to make x the subject (work out its value), you need to single out x

1) the first thing that we can do is get rid of the -74

2) do this by adding it on to both sides of the equation. This is called the inverse

2+-74=-72 -74+14x=14x

-72=14x

3) to get x on its own, we now need to get rid of the 14

REMEMBER: 14x = 14×x

4) We do the inverse by dividing both sides by 14

-72÷14=-5.142...

its surprising that its not an integer

5.142=x

x=5.142

PLEASE LET ME KNOW IF THIS IS CORRECT

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A sample of 11001100 computer chips revealed that 62b% of the chips fail in the first 10001000 hours of their use. The company's

STALIN [3.7K]

Answer:

Rule

If;

P-value > significance level --- accept Null hypothesis

P-value < significance level --- reject Null hypothesis

Z score > Z(at 90% confidence interval) ---- reject Null hypothesis

Z score < Z(at 90% confidence interval) ------ accept Null hypothesis

Null hypothesis: H0 = 0.60

Alternative hypothesis: Ha <> 0.62

z score = 1.35

P value = P(Z<-1.35) + P(Z>1.35) = 0.0885 + 0.0885= 0.177

Since z at 0.10 significance level is between -1.645 and +1.645 and the z score for the test (z = 1.35) falls with the region bounded by Z at 0.1 significance level. And also the two-tailed hypothesis P-value is 0.177 which is greater than 0.1. Then we can conclude that we don't have enough evidence to FAIL or reject the null hypothesis, and we can say that at 0.10 significance level the null hypothesis is valid.

Question; A sample of 1100 computer chips revealed that 62% of the chips fail in the first 1000 hours of their use. The company's promotional literature states that 60% of the chips fail in the first 1000 hours of their use. The quality control manager wants to test the claim that the actual percentage that fail is different from the stated percentage. Determine the decision rule for rejecting the null hypothesis, H0, at the 0.10 level.

Step-by-step explanation:

Given;

n=1100 represent the random sample taken

Null hypothesis: H0 = 0.60

Alternative hypothesis: Ha <> 0.62

Test statistic z score can be calculated with the formula below;

z = (p^−po)/√{po(1−po)/n}

Where,

z= Test statistics

n = Sample size = 1100

po = Null hypothesized value = 0.60

p^ = Observed proportion = 0.62

Substituting the values we have

z = (0.62-0.60)/√{0.60(1-0.60)/1100}

z = 1.354

z = 1.35

To determine the p value (test statistic) at 0.01 significance level, using a two tailed hypothesis.

P value = P(Z<-1.35) + P(Z>1.35) = 0.0885 + 0.0885= 0.177

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3 years ago

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Marianna [84]

I think is the 3rd sorry if I’m wrong

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Answer:

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3 years ago

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Step-by-step explanation:

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4 years ago

Gwar [14]

Answer:

1,3,4

Step-by-step explanation:

ıf we rearrange formula we can obtain

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t=pv/nr

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2 years ago