ans is b...multiply eqn 1 by -2 and eqn 2 by 3
=》 -6x + 10y = 4...eqn 3
=》 6x + 3y = 9...eqn 4
add eqn 3 and 4...
=》13y = 13
=》y =1 and x = 1
1. diginity
2.require
3.tuition
Answer:
The equation of the line that passes through the points (0, 3) and (5, -3) is 
.
Step-by-step explanation:
From Analytical Geometry we must remember that a line can be formed after knowing two distinct points on Cartesian plane. The equation of the line is described below:
(Eq. 1)
Where:
- Independent variable, dimensionless.
- Dependent variable, dimensionless.
- Slope, dimensionless.
- y-Intercept, dimensionless.
If we know that 
and 
, the following system of linear equations is constructed:
(Eq. 2)
(Eq. 3)
The solution of the system is: , 
. Hence, we get that equation of the line that passes through the points (0, 3) and (5, -3) is .
Answer:
(x-5) (x-2)
Step-by-step explanation:
x^2 (-2x-5x) +10
basically you will write the equation down and then to double check multiply the x and then the -5 into (x-2). this can be repetitive if you get it wrong so try to do numbers that make sense.
