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Nataly [62]
4 years ago
15

A potential energy function is given by U(x)=(3.00J)x+(1.00J/m^2)x^3. What is the force function F(x) (in newtons) that is assoc

iated with this potential energy function? Express your answer in terms of x, where x in meters.
Physics
1 answer:
snow_lady [41]4 years ago
4 0

Answer:

F(x)=-3 N -(3N/m^2) x^2

Explanation:

The force is equal to the negative of the derivative of the potential energy function:

F=-\frac{dU}{dx}

In this problem, the potential energy function is

U(x)=3 x + 1 x^3

Therefore, the force function is:

F(x)=-\frac{dU}{dx}=-\frac{d}{dx}(3x+1x^3)=-3-3x^2

So, adding the units of measurement,

F(x)=-3 N -(3N/m^2) x^2

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