Answer:
OBr₂
Explanation:
<em>The ionic character depends on the difference of electronegativity between the elements. The higher ΔEN, the greater the ionic character.</em>
SBr₂
ΔEN = |EN(S)-EN(Br)| = |2.5-2.8| = 0.3
OBr₂
ΔEN = |EN(O)-EN(Br)| = |3.5-2.8| = 0.7
SeCl₂
ΔEN = |EN(Se)-EN(Cl)| = |2.4-3.0| = 0.6
TeI₂
ΔEN = |EN(Te)-EN(I)| = |2.1-2.5| = 0.4
SCl₂
ΔEN = |EN(S)-EN(Cl)| = |2.5-3.0| = 0.5
OBr₂ is the molecule with the most ionic character.
Longer, this is because the H in HNO2 is bonded with an oxygen, no longer allowing this structure to have a resonance structure.
NO2 on the other hand has one double bond and one single bond, so it has a resonance structure. And resonance structures are actually one structure so there isn't really a single and double bond, it's actually a 1 and 1/2 bond that calls for a higher bond order.
And I higher bond order will result in a shorter lengths!
I hope this helps out!!! And just out of curiosity, is this off of an AP FRQ packet??
Answer:
They have the chance to inhale toxic fumes secreted by the mixture.
Explanation:
