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natulia [17]
4 years ago
6

If one of the station models were to show that the barometric pressure was steadily dropping and the current weather condition s

howed a slight drizzle with the temperature of 65 degrees what would you expect the weather to be over the next 6 hours
Chemistry
1 answer:
MArishka [77]4 years ago
7 0
The weather would be around the same maybe dropping 5 degrees
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Describe the three types of system: a.open: b.closed: c. Isolated:
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A thermos bottle uses a ______ to keep heat in the thermos
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Do you think lava or water formed the Chanel on Mars? And why? I’ll give brainliest
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3 years ago
If a solution of HF (Ka=6.8×10−4) has a pH of 2.90, calculate the concentration of hydrofluoric acid.
fgiga [73]

Answer: 0.0023

Explanation:

I just answered this very same question. You can read my answer here: brainly.com/question/12077289.

1) First, you must write the balanced equilibrium equation, which will let you to determine the mole ratios of the different species in solution:

    HF ⇆ H⁺ + F⁻

Therefore, the mole ratio is: 1 HF: 1 H⁺ : 1  F⁻

2) Second, write the equilibrium constant of the acid, Ka, which will permit you to state the relationship of the concentrations in equilibrium:

        Ka = [H⁺] [F⁻] / [HF]

   [HF] is the searched concentration of the hydrofluoric acid

   From the mole ratio of the balanced chemical equation [H⁺] = [F⁻]

       Hence:

       Ka = [H⁺] [H⁺] / [HF] = [H⁺]² / [HF]

3) From the pH value you can calculate [H⁺],  using the definition:

  •    pH= - log [H⁺]
  •    Substitute: 2.90 = - log [H⁺]

 

 Clear [H⁺] using logarithm properties:

         [H^+]=10^{-2.90}=0.00126

4) Now you can substitute [H⁺] and the value of Ka in the equation for Ka:

   Ka = [H⁺]² / [HF] ⇒ [HF] = [H⁺]² / Ka = (0.00126)² / (6.8×10⁻⁴) = 0.00233.

Since the value of Ka has two significant figures, you must report the answer with two significan figures, i.e. 0.0023

7 0
3 years ago
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