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ella [17]
3 years ago
10

Help I need to show work!

Chemistry
1 answer:
lubasha [3.4K]3 years ago
6 0

Answer:

a. Combustion.

b. m_C=3.057gC

c. m_H=3.67gH

Explanation:

Hello.

a. In this case, given the reaction by which propane is converted into carbon dioxide and water:

C_3H_8+5O_2 \rightarrow 3CO_2+4H_2O

It is known as a combustion reaction since it is about a fuel (here propane) which is burnt by the oxygen contained in the air (21%).

b. Since the carbon dioxide contains all the carbon in the products based on the law of conservation of mass, the yielded grams are computed via a mole mass relationship:

m_C=11.21gCO_2*\frac{12gC}{44gCO_2}=3.057gC

Since 44 grams of carbon dioxide contain 12 grams of carbon.

c. As well as b., all the hydrogen is  given off in form of water, thus, the required mass turns out:

m_H=33.0gH_2O*\frac{2gH}{18gH_2O}=3.67gH

Since 18 grams of water contain 2 grams of hydrogen.

Best regards.

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3. The mass of ethanol required is approximately 0.522869 g

The mass of ethanoic acid required is approximately 0.68156 g

4. The mass of iron (III) oxide required is approximately 285.952.189.095 tonnes

5. The mass of silver nitrate required is approximately 14.53 grams

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3. The 1 mole of ethanol and 1 mole of ethanoic acid combines to form 1 mole of ethyl ethanoate

The number of moles of ethyl ethanoate in 1 gram of ethyl ethanoate, n = 1 g/(88.11 g/mol) = 1/88.11 moles

∴ The number of moles of ethanol = 1/88.11 moles

The number of moles of ethanoic acid = 1/88.11 moles

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4. 1 mole of iron(III) oxide reacts with 1 mole of CO₂ to produce 1 mole of iron

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5. The number of moles of NaCl in 5 grams of NaCl = 5 g/58.44 g/mol = 0.0855578371 moles

The mass of silver nitrate required, m = 169.87 g/mol × 0.0855578371 moles ≈ 14.53 grams

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