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natali 33 [55]
3 years ago
10

Describe a sequence of transformations that maps ABC to A'B'C'.

Mathematics
1 answer:
Sphinxa [80]3 years ago
7 0

The correct answer is " (1) Reflect ABC across the x-axis and call this new triangle A'B'C'. (2) Translate A'B'C' 2 units right and 6 units up so that its image is A''B''C''. "


It is assumed that the points are

A in ABC is (1,9), B in ABC is (3,12), and C in ABC is (4,4). 


A'' in A''B''C'' is (3,-3), B'' in A''B''C'' is (5,-6), and C'' in A''B''C'' is (6,2).


Both triangles are congruent. Since they are congruent, there are no contractions nor dilations occured. After rotating clockwise, we get A"C"B". So we need to reflect it to get A"B"C"


hope this helped :D

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What value is equivalent to 108-8x(5-2)-60
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Answer:

-28    +    -1    =    -29

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     -4    +    -7    =    -11

     -2    +    -14    =    -16

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     4    +    7    =    11

     7    +    4    =    11

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Step-by-step explanation:

6 0
3 years ago
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The sample space, S, for flipping a fair coin three times is shown
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Answer: \frac{7}{8}

Step-by-step explanation:

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3 years ago
R + (-5r)<br><br> Please explain how it's done.
Lisa [10]

Answer:

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r (-4)

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7 0
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