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Eduardwww [97]
4 years ago
10

Generally speaking, which group would have the lowest electronegativity values in a period? Group 1 Group 3 Group 14 Group 17

Chemistry
2 answers:
ivolga24 [154]4 years ago
7 0

Answer:

The answer would be group 1 I just took the test and that is the correct answer!!

Explanation:

KatRina [158]4 years ago
6 0

Here we have get the group which has the lowest electronegativity in a period among the given groups.

The group 1 elements are more electropositive in nature the removal one electron will have its previous nobel gas configuration.    

The electronegativity is not an inherent property of the isolated atom. This concept has been generated for a convenient study of hetero-molecular covalent bond.

The electronegativity is defined as a measure of the tendency of an atom in a molecule to attract the electrons involved in the chemical bond formation.

The group 1 elements are H, Li, Na, K, Rb, Cs and Fr.

The group 3 elements are Sc, Y, La, Ac.

The group 14 elements are C, Si, Ge, Sn, Pb.

The group 17 elements are F, Cl, Br, I, At.

Now the group 1 elements have the valence shell electron ns¹ in the period.

Similarly, group 3, have the valence shell electrons ns²(n-1)d⁰⁻¹⁰(n-2)f⁰⁻¹⁴

group 14 have the valence shell electrons ns²np²

and group 17 have the valence shell electrons ns²np⁵.

Thus the group 1 elements are more electropositive in nature the removal one electron will have its previous nobel gas configuration.    

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Part A In a particular experiment at 300 ∘C, [NO2] drops from 0.0138 to 0.00886 M in 374 s . The rate of disappearance of NO2 fo
sweet-ann [11.9K]

Answer:

The rate of disappearance of NO_2 for this period is-1.32\times 10^{-5} M/s

Explanation:

Initial concentration of NO_2 = x = 0.0138 M

Final concentration of NO_2 = y = 0.00886 M

Time elapsed during change in concentration = Δt = 374 s

Change in concentration ,\Delta [NO_2]= y - x = 0.00886 - 0.0138 M = -0.00494 M

The rate of disappearance of NO_2 for this period is:

\frac{\Delta [NO_2]}{\Delta t}=\frac{-0.00494 M}{374 s}=-1.32\times 10^{-5} M/s

4 0
3 years ago
When silver nitrate is added to an aqueous solution of magnesium chloride, a precipitation reaction occurs that produces silver
Aloiza [94]

Answer:

103.62 g of AgCl.

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

2AgNO3 + MgCl2 —> 2AgCl + Mg(NO3)2

Step 2:

Determination of the mass of MgCl2 that reacted and the mass of AgCl produced from the balanced equation.

This is illustrated below:

Molar mass of MgCl2 = 24 + (2x35.5) = 95 g/mol

Mass of MgCl2 from the balanced equation = 1 x 95 = 95 g

Molar mass of AgCl = 108 + 35.5 = 143.5 g/mol

Mass of AgCl from the balanced equation = 2 x 143.5 = 287 g

Thus, from the balanced equation above,

95 g of MgCl2 reacted to produce 287 g of AgCl.

Step 3:

Determination of the mass of AgCl produced from the reaction of 34.3 g of MgCl2.

The mass of AgCl produced from the reaction can be obtained as follow:

Form the balanced equation above,

95 g of MgCl2 reacted to produce 287 g of AgCl.

Therefore, 34.3 g of MgCl2 will react to produce = (34.3 x 287)/95 = 103.62 g of AgCl.

Therefore, 103.62 g of AgCl were produced from the reaction.

8 0
4 years ago
How many grams of H2 are needed to produce 13.33g of NH3?
Zanzabum

The reaction to form NH3 is : N2 + 3H2-> 2NH3 12,33g NH3 is 12,33/17,03=0,3 =0,724 moles of NH3 moles NH3. So you need 1,5*0,724 = 1,086 moles H2 1,086*2,016 = 2,189 g of H2 is needed ro form 12,33 g NH3

3 0
4 years ago
49.Which of the following statements regarding chemical equilibrium is true?
crimeas [40]
A asystem at equilibrium stops
8 0
4 years ago
What would be your reaction to a claim that a new element had been discovered, and it fit between tin (Sn) and antimony (Sb) in
Anton [14]

Answer:

As explained

Explanation:

My reaction will be positive and I will feel elated that a new elements has been discovered as this will be a modification of the earlier claim by berzelius and the likes that there are over 106 known elements ; Metal, Non Metals and Metalloids.

However, fitting the new discovered element in between Tin and antimony may be an issue, as the physical properties of the new elements has to be known, its melting point, metals or non metals as this is paramount to be able to classify the elements. if the elements fits in between tin and antimony, it is an indication that the elements is mot likely a metal or non-mental and may belong to group IVB or VB. Another issue is, the discoverer will have to create his own periodic table to be able to stand in with the discovery of Dimitriy Mendelev.

8 0
4 years ago
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