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4 years ago

Generally speaking, which group would have the lowest electronegativity values in a period? Group 1 Group 3 Group 14 Group 17

Chemistry

2 answers:

ivolga24 [154]4 years ago

7 0

Answer:

The answer would be group 1 I just took the test and that is the correct answer!!

Explanation:

KatRina [158]4 years ago

6 0

Here we have get the group which has the lowest electronegativity in a period among the given groups.

The group 1 elements are more electropositive in nature the removal one electron will have its previous nobel gas configuration.

The electronegativity is not an inherent property of the isolated atom. This concept has been generated for a convenient study of hetero-molecular covalent bond.

The electronegativity is defined as a measure of the tendency of an atom in a molecule to attract the electrons involved in the chemical bond formation.

The group 1 elements are H, Li, Na, K, Rb, Cs and Fr.

The group 3 elements are Sc, Y, La, Ac.

The group 14 elements are C, Si, Ge, Sn, Pb.

The group 17 elements are F, Cl, Br, I, At.

Now the group 1 elements have the valence shell electron ns¹ in the period.

Similarly, group 3, have the valence shell electrons ns²(n-1)d⁰⁻¹⁰(n-2)f⁰⁻¹⁴

group 14 have the valence shell electrons ns²np²

and group 17 have the valence shell electrons ns²np⁵.

Thus the group 1 elements are more electropositive in nature the removal one electron will have its previous nobel gas configuration.

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We want to calculate the concentrations of all species in a 0.58 M Na 2 SO 3 (sodium sulfite) solution. The ionization constants

NeX [460]

Explanation:

Reaction equation is as follows.

$Na_{2}SO_{3}(s) \rightarrow 2Na^{+}(aq) + SO^{2-}_{3}(aq)$

Here, 1 mole of $Na_{2}SO_{3}$ produces 2 moles of cations.

$[Na^{+}] = 2[Na_{2}SO_{3}] = 2 \times 0.58$

= 1.16 M

$[SO^{2-}_{3}] = [Na_{2}SO_{3}]$ = 0.58 M

The sulphite anion will act as a base and react with $H_{2}O$ to form $HSO^{-}_{3}$ and $OH^{-}$ .

As, $K_{b} = \frac{K_{w}}{K_{a_{2}}}$

= $\frac{10^{-14}}{6.3 \times 10^{-8}}$

= $1.59 \times 10^{-7}$

According to the ICE table for the given reaction,

$SO^{2-}_{3} + H_{2}O \rightleftharpoons HSO^{-}_{3} + OH^{-}$

Initial: 0.58 0 0

Change: -x +x +x

Equilibrium: 0.58 - x x x

So,

$K_{b} = \frac{[HSO^{-}_{3}][OH^{-}]}{[SO^{2-}_{3}]}$

$1.59 \times 10^{-7} = \frac{x^{2}}{0.58 - x}$

$x^{2} = 1.59 \times 10^{-7} \times (0.58 - x)$

x = 0.0003 M

So, x = $[HSO^{-}_{3}] = [OH^{-}]$ = 0.0003 M

$[SO^{2-}_{3}]$ = 0.58 - 0.0003

= 0.579 M

Now, we will use $[HSO^{-}_{3}]$ = 0.0003 M

The reaction will be as follows.

$HSO^{2-}_{3} + H_{2}O \rightleftharpoons H_{2}SO_{3} + OH^{-}$

Initial: 0.0003

Equilibrium: 0.0003 - x x x

$K_{b} = \frac{x^{2}}{0.0003 - x}$

$K_{b} = \frac{K_{w}}{K_{a_{1}}}$

= $\frac{10^{-14}}{1.4 \times 10^{-2}}$

= $7.14 \times 10^{-13}$

Therefore, $7.14 \times 10^{-13} = \frac{x^{2}}{0.0003 - x}$

As, x <<<< 0.0003. So, we can neglect x.

Therefore, $x^{2} = 7.14 \times 10^{-13} \times 0.0003$

= $0.00214 \times 10^{-13}$

x = $0.0146 \times 10^{-6}$

x = $[OH^{-}] = [H_{2}SO_{3}]$ = $1.46 \times 10^{-8}$

$[H^{+}] = \frac{10^{-14}}{[OH^{-}]}$

= $\frac{10^{-14}}{0.0003}$

= $3.33 \times 10^{-11}$ M

Thus, we can conclude that the concentration of spectator ion is $3.33 \times 10^{-11}$ M.

5 0

3 years ago

Characteristics of matter that cannot be changed are called

olchik [2.2K]

It is called Mass.

Among the physical characteristics of a matter which includes Weight, Mass, Volume, and Density the only characteristic that does not change is the mass. The mass of an object never change from place to place. All the objects have a mass and that is why there is a weight but it changes depends on the gravity. Mass don't.

5 0

3 years ago

Oxygen is a reactant of___(1)___while being the product for___(2)___.

yuradex [85]

Answer:

Oxygen is a reactant of cellular respiration, while being the product for photosynthesis

Explanation:

Photosynthesis

carbon + water + sunlight -> oxygen and glucose

Cellular respiration

oxygen + glucose -> carbon + water + ATP

6 0

3 years ago

When convex mirrors are used for security purposes, the images they form

konstantin123 [22]

Answer:false

Explanation:

3 0

3 years ago

The following diagram represents the potential energy for the reaction:

Sloan [31]

A is the answer I reckon

3 0

3 years ago

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