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Rus_ich [418]
3 years ago
6

The atomic mass of an element is 32.07 u and its atomic number is 16. The number of protons contained in the nucleus of an atom

of this element is
(A) 16
(B) 31
(C) 32
(D) 48
Chemistry
2 answers:
bulgar [2K]3 years ago
3 0

I THINK IT IS 16 BECAUSE THE ATOMIC NUMBER AND THE NUMBER OF PROTONS ARE THE SAME
HACTEHA [7]3 years ago
3 0
Atomic number = number of electrons = number of protons( by JJ thomson's theory)

Thus, the number of protons is 16
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20 PTS<br> SHOW ALL WORK AND EXPLAIN PLZ<br><br> What is the molar mass of chlorine gas?
Anastaziya [24]
Chlorine= 35.5 +35.3= 71 a.m.u.
5 0
3 years ago
You take a bottle of soft drink out of your refrigerator. The contents are liquid and stay liquid, even when you shake them. Pre
inna [77]

Answer:

The correct answer is due to the difference in pressure inside and outside the bottle.

Explanation:

Liquids have melting and boiling points that depend on pressure and temperature. The pressure inside the bottle is higher than the pressure outside. This causes the melting point to drop, making the liquid freeze at a lower temperature than if it were at atmospheric pressure, and therefore has a lower temperature than it would freeze at atmospheric pressure. When the bottle is uncovered, the liquid becomes an atmospheric pressure, and due to the temperature acquired when the bottle was closed the liquid freezes.

Have a nice day!

3 0
3 years ago
PLEASE HELP!
Tanzania [10]
Molar mass:

KCl = 74.55 g/mol

KClO3 = 122. 55 g/mol

  <span>Calculation of the mass of KClO3 :</span>

<span>2 KClO3 =  2 KCl + 3 O2</span>

2* 122.55 g KClO3 ------------------ 2 * 74.55 g KCl
mass KClO3 ?? --------------------- 25.6 g KCl

mass KClO3 = 25.6 * 2 * 122.55 / 2 * 74.55

mass KClO3 = 6274.56 / 149.1

mass = 42.082 g of  KClO3

Therefore:

1 mole KClO3 ---------------------- 122.55 g
?? moles KClO3 ------------------- 42.082 g

moles KClO3 = 42.082 * 1 / 122.55

moles KClO3 = 42.082 / 122.55

=> 0.343 moles of KClO3


Answer C

hope this helps!

3 0
3 years ago
What is the volume of HCl gas required to react with excess magnesium metal to produce 6.82 L of hydrogen gas at 2.19 atm and 35
prohojiy [21]

Answer:

Explanation:

2 HCl(g) + Mg(s) → MgCl₂(s) + H₂(g)

Let's calculate the quantity of mole of produced hydrogen with the Ideal Gases Law

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2.19 atm . 6.82L = n . 0.082 . 308K

(2.19 atm . 6.82L) / (0.082 . 308K) = n

0.591 mol = n

1 mol of H₂ gas came from 2 mol of hydrochloric, so, 0.591 mol came from the double of mole

0.591 .2 = 1.182 mole of acid.

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1.182 mole are (36.45 g/m . 1.182g ) contained in 43.1 g

Density HCl = HCl mass / HCl volume

0,118 g/mL = 43.1 g / HCl volume

43.1 g / 0.118 g/mL = 365.3 mL (HCl volume)

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