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2 years ago

Why is it better to use the metric system, rather than the English system, in scientific measurement?

Chemistry

2 answers:

nasty-shy [4]2 years ago

6 0

Answer:

Explanation:

Hello,

English system is indeed based on the metric system because they look for reference stuff to get the measurements, for instance, a foot equals 30.48 cm, but a common 30-cm rule measures every 1 cm, so the metric system also provides more accurate measurements. An other example lies on the measurement of mass, a pound which equals 453.59 g is appropriated to measure middle amounts of masses, but for example, in qualitative analysis we tend to measure amounts below about 0.10 g (0.022 lb) so it is easier for us in science to use the metric system in addition to the straightforwardness of the reporting data in 10-based notation (scientific notation).

Best regards.

frez [133]2 years ago

3 0

The metric system is based on powers of 10 so it is much easier to convert units, often just by moving the decimal point.

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Answer:

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Explanation:

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The decomposition of nitrogen dioxide is described by the following chemical equation: Suppose a two-step mechanism is proposed

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If 57.3 l of 0.497 m koh is required to completely neutralize 39.5 l of a CH3COOH solution. What is the molarity of the acetic a

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The molarity of the solution will be 0.72 m.

The majority of reactions take place in solutions, making it crucial to comprehend how the substance's concentration is expressed in a solution when it is present. The number of chemicals in a solution can be stated in a variety of ways, including.

The symbol for it is M, and it serves as one of the most often used concentration units. Its definition states how many moles of solute there are in a liter of solution.

Given data:

$V_{1} =57.3 L\\V_{2} = 39.5 L\\M_{1} = 0.497 m\\\\M_{2} = ?$

Molarity can be determined by the formula:

$M_{1} V_{1} = M_{2} V_{2}$

where, M is molarity and V is volume.

Put the value of given data in above equation.

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The first step is to balance the equation:

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element left side right side

C 3 3
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