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Novosadov [1.4K]
3 years ago
7

A circle has the circumference of 3.75 in. What is the diameter of the circle? (Use 3.14 for p. Round to the nearest tenth.) a.

1.9 in c. 0.6 in b. 1.2 in d. 7.5 in
Mathematics
1 answer:
HACTEHA [7]3 years ago
7 0

Answer:

<h2>b. 1.2 in</h2>

Step-by-step explanation:

The formula of a circumference:

C=d\pi

<em>d</em> - diameter

We have <em>C = 3.75 in</em><em>.</em>

Substitute:

d\pi=3.75\qquad\text{use}\ \pi\approx3.14\\\\3.14d=3.75\qquad\text{divide both sides by 3.14}\\\\d=\dfrac{3.75}{3.14}\\\\d=\dfrac{375}{314}\\\\d\approx1.2\ in

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ACDF is a trapezoid and
Sholpan [36]

Answer:

x = 7

Step-by-step explanation:

See the attached figure.

As shown: A C D F is a trapezoid and BE is a mid-segment.

The mid-segment of the trapezoid is the average of its bases.

BE = 0.5 ( A F + C D)

Given: CD = 18 , BE = 2x + 10   and   A F = 6x - 12

So,

2x + 10 = 0.5 ( 18 + 6x - 12)

Solve for x

2x + 10 = 0.5 (6 + 6x)

2x + 10 = 3 + 3x

10 - 3 = 3x - 2x

∴ x = 7

<u>So, the value of x is 7</u>

8 0
3 years ago
II'll mark brainliest who is the first to answer both questions correctly.
Strike441 [17]

Answer:

A) The probability that each player gets an ace, a 2 and a 3 with the order unimportant = (72/1925) = 0.0374

B) The probability of winning the jackpot = (1/1200) = 0.0008333

Step-by-step explanation:

A) There are four Aces, four 2's, and four 3's, forming a set of 12 cards

These cards are to be divided at random between 4 players.

What is the probability that each player gets an ace, a 2 and a 3.

We start with the first player, the probability of these cards for the first player, with order not important (because order isn't important, there are 6 different arrangement of the 3 cards)

6 × (4/12) × (4/11) × (4/10) = (16/55)

Then the second player getting that same order of cards

6 × (3/9) × (3/8) × (3/7) = (9/28)

Third player

6 × (2/6) × (2/5) × (2/4) = (2/5)

Fourth player

6 × (1/3) × (1/2) × (1/1) = 1

Probability that each of the players get different cards is then a multiple of the probabilities obtained above

= (16/55) × (9/28) × (2/5) × 1

= (288/7700) = (72/1925) = 0.0374

B) The concluding part of the B question.

To win the jackpot, the numbers on your ticket must match the three white balls and the SuperBall. (You don't need to match the white balls in order). If you buy a ticket, what is your probability of winning the jackpot?

Probability of wimning the jackpot is a product the probability of getting the 3 white balls correctly (order unimportant) and the probability of picking the right red superball

Probability of picking 3 white balls from 10

First slot, any of the 3 lucky numbers can fill this slot, (3/10)

Second slot, only 2 remaining lucky numbers can fill this slot, (2/9)

Third slot, only 1 remaining lucky number can fill this slot, (1/8)

(3/10) × (2/9) × (1/8) = (1/120)

Probability of picking the right red superball

(1/10)

Probability of winning the jackpot = (1/120) × (1/10) = (1/120) × (1/10) = (1/1200) = 0.0008333

Hope this Helps!!!

5 0
3 years ago
What is 60% of 1,545
Lyrx [107]

Answer: 927

Step-by-step explanation:

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1 year ago
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Answer:

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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