<h3>Answer: Choice C</h3>
RootIndex 12 StartRoot 8 EndRoot Superscript x
12th root of 8^x = (12th root of 8)^x
![\sqrt[12]{8^{x}} = \left(\sqrt[12]{8}\right)^{x}](https://tex.z-dn.net/?f=%5Csqrt%5B12%5D%7B8%5E%7Bx%7D%7D%20%3D%20%5Cleft%28%5Csqrt%5B12%5D%7B8%7D%5Cright%29%5E%7Bx%7D)
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Explanation:
The general rule is
![\sqrt[n]{x} = x^{1/n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%20%3D%20x%5E%7B1%2Fn%7D)
so any nth root is the same as having a fractional exponent 1/n.
Using that rule we can say the cube root of 8 is equivalent to 8^(1/3)
![\sqrt[3]{8} = 8^{1/3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8%7D%20%3D%208%5E%7B1%2F3%7D)
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Raising this to the power of (1/4)x will have us multiply the exponents of 1/3 and (1/4)x like so
(1/3)*(1/4)x = (1/12)x
In other words,
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From here, we rewrite the fractional exponent 1/12 as a 12th root. which leads us to this
![8^{(1/12)x} = \sqrt[12]{8^{x}}](https://tex.z-dn.net/?f=8%5E%7B%281%2F12%29x%7D%20%3D%20%5Csqrt%5B12%5D%7B8%5E%7Bx%7D%7D%20)
![8^{(1/12)x} = \left(\sqrt[12]{8}\right)^{x}](https://tex.z-dn.net/?f=8%5E%7B%281%2F12%29x%7D%20%3D%20%5Cleft%28%5Csqrt%5B12%5D%7B8%7D%5Cright%29%5E%7Bx%7D%20)
The answer is: [C]: " ⁷/₆ " .
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Note:
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(5/3) - (1/2) = ? ;
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The LCD (lowest common denominator) of "2 and 3" is "6" ;
So we need to rewrite EACH fraction in the problem as a fraction with "6" in the denominator ;
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(5/3) = (?/6) ? ; (6÷3=2) ; (5/3) = (5*2)/(3*2) = 10/6 ;
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(1/2) = (?/6) ? ; (6÷2=3) ; (1/2) = (1*3)/(2*3) = 3/6 ;
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Rewrite the problem: " (5/3) - (1/2) " ; as:
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10/6 - 3/6 ;
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10/6 - 3/6 = (10 - 3) / 6 = (7/6) = 1 ⅙ .
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The answer is: " ⁷/₆ " ; or, write as: " 1 ⅙ " ; which corresponds to:
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Answer choice: [C]: " ⁷/₆ " .
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First two are scalene last one is isosceles.
Answer: each width = 10, each length = 21
Explanation: from the question we know that L=2w + 1 and we also know that a rectangle has the perimeter of 62 when we plug it in the equation we will get 62= 2(2w+1+w) we will multiply the 2 now and we will get 62=4w+2+2w we will combine like terms and we will minus two from both sides ending up with 60=6w we will divide six from both sides and we will get w=10 then we will use l=2w+1 to find the length and it will be 21
