Answer: Choice CThe non-pencil part of the compass is placed at point G. The compass must be kept the same width that was used to form the arc shown. The idea is to draw another arc so that it starts above G (so its on the opposite side of point A) and traces out a similar path as the arc in the diagram.
Check out the attached image to see what I mean. The new second arc is shown in red.
Take the vector u = <ux, uy> = <4, 3>.
Find the magnitude of u:
||u|| = sqrt[ (ux)^2 + (uy)^2]
||u|| = sqrt[ 4^2 + 3^2 ]
||u|| = sqrt[ 16 + 9 ]
||u|| = sqrt[ 25 ]
||u|| = 5
To find the unit vector in the direction of u, and also with the same sign, just divide each coordinate of u by ||u||. So the vector you are looking for is
u/||u||
u * (1/||u||)
= <4, 3> * (1/5)
= <4/5, 3/5>
and there it is.
Writing it in component form:
= (4/5) * i + (3/5) * j
I hope this helps. =)
Answer:
in my opinon, this table is proportional
Answer:
Step-by-step explanation:
No
3(4x - 2) = 12x - 4 ≠ 12x -2