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lozanna [386]
3 years ago
9

4(2+3)-[7-[4-(8+5)]can you help me with this question

Mathematics
2 answers:
Gnesinka [82]3 years ago
7 0
4(2 + 3) - [7 - [4 - (8 + 5)]]

First, do the parentheses:

4(5) - [7 - [4 - 12]]

Then complete the rest from the inside out:

20 - [7 - (-8)]

20 - 15 = 5
natali 33 [55]3 years ago
6 0
If you simplify or evaluate the problem you get 4. You should check out math way.
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<h3>Answer: Choice C</h3>

RootIndex 12 StartRoot 8 EndRoot Superscript x

12th root of 8^x = (12th root of 8)^x

\sqrt[12]{8^{x}} = \left(\sqrt[12]{8}\right)^{x}

=========================================

Explanation:

The general rule is

\sqrt[n]{x} = x^{1/n}

so any nth root is the same as having a fractional exponent 1/n.

Using that rule we can say the cube root of 8 is equivalent to 8^(1/3)

\sqrt[3]{8} = 8^{1/3}

-----

Raising this to the power of (1/4)x will have us multiply the exponents of 1/3 and (1/4)x like so

(1/3)*(1/4)x = (1/12)x

In other words,

\left(8^{1/3}\right)^{(1/4)x} = 8^{(1/3)*(1/4)x}

\left(8^{1/3}\right)^{(1/4)x} = 8^{(1/12)x}

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From here, we rewrite the fractional exponent 1/12 as a 12th root. which leads us to this

8^{(1/12)x} = \sqrt[12]{8^{x}}

8^{(1/12)x} = \left(\sqrt[12]{8}\right)^{x}

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Fofino [41]
The answer is:  [C]:  " ⁷/₆ " .
____________________________________
  Note:
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   (5/3) - (1/2) = ? ;
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The LCD (lowest common denominator) of "2 and 3" is "6" ;

So we need to rewrite EACH fraction in the problem as a fraction with "6" in the denominator ;
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 (5/3) = (?/6) ?  ;  (6÷3=2) ;  (5/3) = (5*2)/(3*2) = 10/6 ;
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(1/2) = (?/6) ? ; (6÷2=3) ;  (1/2) = (1*3)/(2*3) = 3/6 ;
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Rewrite the problem:   "    (5/3) - (1/2) " ;  as:
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   10/6 - 3/6  ;
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    10/6 - 3/6 = (10 - 3) / 6 = (7/6) = 1 ⅙ .
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The answer is:  " ⁷/₆ " ;  or, write as:   " 1 ⅙ " ; which corresponds to: 
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3 years ago
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