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vitfil [10]
3 years ago
12

The price of a mobile phone decreased from $375 to $250 during a clearance sale. What is the percent of decrease in the price?

Mathematics
1 answer:
Tresset [83]3 years ago
4 0
So decrease is 375-250=75

so convert 75/375 to percent
percent means part out of 100 so 
x/100=x%

divide 125/375=0.3333/1

multiply by 100/100=33/100=33%

the answer is 33% or B
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Please help me with this question and please tell me how I would put this into a calculator please...
AnnyKZ [126]

Answer:

6

Step-by-step explanation:

\frac{2}{3}x+4=\frac{2}{3} *\frac{3}{1}+4 = 2+4=6

3 0
3 years ago
10 3/9- 10 2/5 Im to lazy to do it please help me out.
coldgirl [10]

Answer:

\boxed{ \ -  \frac{3}{45} }

Step-by-step explanation:

10 3/9 - 10 2/5

we need to convert mixed fractions to improper fractions

10 \frac{3}{9}  =  \frac{10 \times 9 + 3}{9}  =  \frac{93}{9}

10 \frac{2}{5}  =  \frac{10 \times 5 + 2}{5}  =  \frac{52}{5}

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The result of 10 3/9- 10 2/5 is - 3/45

8 0
2 years ago
If f(x)=x^2-11, for what values of z is f(x) < 25?
GuDViN [60]

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5 0
3 years ago
How to solve 2v 14=20
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3 years ago
A simple random sample of items resulted in a sample mean of . The population standard deviation is . a. Compute the confidence
Varvara68 [4.7K]

Answer:

(a): The 95% confidence interval is (46.4, 53.6)

(b): The 95% confidence interval is (47.9, 52.1)

(c): Larger sample gives a smaller margin of error.

Step-by-step explanation:

Given

n = 30 -- sample size

\bar x = 50 -- sample mean

\sigma = 10 --- sample standard deviation

Solving (a): The confidence interval of the population mean

Calculate the standard error

\sigma_x = \frac{\sigma}{\sqrt n}

\sigma_x = \frac{10}{\sqrt {30}}

\sigma_x = \frac{10}{5.478}

\sigma_x = 1.825

The 95% confidence interval for the z value is:

z = 1.960

Calculate margin of error (E)

E = z * \sigma_x

E = 1.960 * 1.825

E = 3.577

The confidence bound is:

Lower = \bar x - E

Lower = 50 - 3.577

Lower = 46.423

Lower = 46.4 --- approximated

Upper = \bar x + E

Upper = 50 + 3.577

Upper = 53.577

Upper = 53.6 --- approximated

<em>So, the 95% confidence interval is (46.4, 53.6)</em>

Solving (b): The confidence interval of the population mean if mean = 90

First, calculate the standard error of the mean

\sigma_x = \frac{\sigma}{\sqrt n}

\sigma_x = \frac{10}{\sqrt {90}}

\sigma_x = \frac{10}{9.49}

\sigma_x = 1.054

The 95% confidence interval for the z value is:

z = 1.960

Calculate margin of error (E)

E = z * \sigma_x

E = 1.960 * 1.054

E = 2.06584

The confidence bound is:

Lower = \bar x - E

Lower = 50 - 2.06584

Lower = 47.93416

Lower = 47.9 --- approximated

Upper = \bar x + E

Upper = 50 + 2.06584

Upper = 52.06584

Upper = 52.1 --- approximated

<em>So, the 95% confidence interval is (47.9, 52.1)</em>

Solving (c): Effect of larger sample size on margin of error

In (a), we have:

n = 30     E = 3.577

In (b), we have:

n = 90    E = 2.06584

<em>Notice that the margin of error decreases when the sample size increases.</em>

4 0
3 years ago
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