Question

Find the sum of the first 8 terms of the sequence an=2(4) ^n-1

Answer 1

Answer:

Step-by-step explanation:

a1=2

r=4

n=8

$s_{8}=2\frac{4^8-1}{4-1} =\frac{2}{3} (4^8-1)=\frac{2}{3} (65536-1)=\frac{2}{3} (65535)=2 \times 21845=43690$