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Anettt [7]
3 years ago
15

A boat has a mass of 4040 kg. Its engines generate a drive force of 4660 N due west, while the wind exerts a force of 880 N due

east and the water exerts a resistive force of 1400 N due east. Take west to be the positive direction. What is the boat's acceleration, with correct sign?
Physics
2 answers:
maxonik [38]3 years ago
6 0

Answer:

Explanation:

Given:

Mass of the boat, m = 4040 kg

The driving force of engine, FB = 4660 N in west = + 4660 N

The force of wind, Fwi = 880 N in east = -880 N

The force of water, Fwa = 1400 N in east = -1400N

Total three forces are acting on the boat

Fnet= Fb+fwi+Fwa

Fnet= 4660 - 880 - 1400

Fnet= +2380N

Acceleration (a) = Force/mass

= 2380/4040

= 0.59m/s2

riadik2000 [5.3K]3 years ago
4 0

Answer: acceleration =0.59m/s2

Direction is due west

Explanation: M = 4040

F1 =4660

F2=1400

F3=880

Net force = F1-(F2 +F3)

= 4660-(1400 + 880)

=2380

Acceleration (a)= F/M

= 2380/4040

= 0.59m/s2

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2 years ago
A cannon fired horizontally at 20 m/s from the top of a cliff lands 80m away. how tall is the cliff
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Answer:

The height of the cliff is, h = 78.4 m

Explanation:

Given,

The horizontal velocity of the projectile, Vx = 20 m/s

The range of the projectile, s = 80 m

The projectile projected from a height is given by the formula

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