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Anettt [7]
2 years ago
15

A boat has a mass of 4040 kg. Its engines generate a drive force of 4660 N due west, while the wind exerts a force of 880 N due

east and the water exerts a resistive force of 1400 N due east. Take west to be the positive direction. What is the boat's acceleration, with correct sign?
Physics
2 answers:
maxonik [38]2 years ago
6 0

Answer:

Explanation:

Given:

Mass of the boat, m = 4040 kg

The driving force of engine, FB = 4660 N in west = + 4660 N

The force of wind, Fwi = 880 N in east = -880 N

The force of water, Fwa = 1400 N in east = -1400N

Total three forces are acting on the boat

Fnet= Fb+fwi+Fwa

Fnet= 4660 - 880 - 1400

Fnet= +2380N

Acceleration (a) = Force/mass

= 2380/4040

= 0.59m/s2

riadik2000 [5.3K]2 years ago
4 0

Answer: acceleration =0.59m/s2

Direction is due west

Explanation: M = 4040

F1 =4660

F2=1400

F3=880

Net force = F1-(F2 +F3)

= 4660-(1400 + 880)

=2380

Acceleration (a)= F/M

= 2380/4040

= 0.59m/s2

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Explanation:

Perhaps the formula should be

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3 years ago
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An iron block of mass 10 kg rests on a wooden plane inclined at 30° to the horizontal. It is found
Kaylis [27]

I assume the 100 N force is a pulling force directed up the incline.

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Then

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Inessa [10]

Answer:

The coefficient of kinetic friction is 0.13

Explanation:

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\sum\overrightarrow{F}=m\overrightarrow{a} (1)

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F_y=ma_y (2)

F_x=ma_x (3)

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F_y=W+n=0

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F_y=(755)(-9.81)+n=0

n=7406.55 N (4)

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F_x=F+f=ma_x

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The negative sign means it's in the opposite direction the horse is pulling

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\mu_k=\frac{|f|}{n}=\frac{961.2}{7406.55}=0.13

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