Answer:
The speed should be reduced by 1/√2 or 0.707 times
Explanation:
The relationship between the kinetic energy, mass and velocity can be represented by the following equation:
K.E = ½m.v²
In this equation, the mass is inversely proportional to the square of the velocity or speed. This means that as the mass increases, the speed reduces by × 2.
Let; initial mass = m1
Final mass = m2
Initial velocity = v1
Final velocity = v2
According to the question, if the mass of the body is doubled i.e. m2 = 2m
½m1v1² = ½m2v2²
½ × m × v1² = ½ × 2m × v2²
Multiply both sides by 2
(½ × m × v1²)2 = (½ × 2m × v2²)2
m × v1² = 2m × v2²
Divide both sides by m
v1² = 2v2²
Divide both sides by 2
v1²/2= v2²
Square root both sides
√v1²/2= √v2²
v1/√2 = v2
v2 = 1/√2 v1
This shows that to maintain the same kinetic energy if the mass is doubled, the speed should be reduced by 1/√2 or 0.707 times.
Answer:
5.45 J
Explanation:
When the 3.4 kg weight is moving with a speed of 1.1 m/s, what is the kinetic energy of the entire system?
RKE = 
where;
RKE =
= 
= 3.75 J
LKE = 
= 
= 1. 7 J
K.E = RKE + LKE
K. E = ( 3.75 + 1.7 ) J
K . E = 5.45 J
I think potential but im not sure
Negative celestial declinations are all positions in the sky that are directly over south surface latitudes.
Sirius is SOUTH of the celestial equator.
During the course of a year, it traces a circular path directly over the parallel of 16° South latitude, taking it over Peru, La Paz in Bolivia, St. Helena island in the Atlantic, Namibia, Angola, Zambia, Mozambique, Malawi, Madagascar, Australia, French Polynesia, American Samoa, and the Pacific Ocean.
