When the object is lifted 6 meters of the ground , then lifted to 12 meters, it is lifted twice as high ( 6 x 2 = 12).
This means the potential energy is also doubled.
Answer:
<h3>0.329m/s</h3>
Explanation:
According to law of conservation of momentum, the momentum of the object before collision is equal to that of the object after collision. Using the formula
m1u1 + m2u2 = (m1+m2)v
m1 and m2 are the masses of the object
u1 and u2 are the respective initial velocities
v is the final velocity
Given
m1 = 0.190kg
u1 = 1.5m/s
m2 = 0.305kg
u2 = -0.401m/s
Substitute
0.19(1.5)+(0.305)(-0.401) = (0.19+0.305)v
0.285 - 0.122305 = 0.495v
0.162695 = 0.495v
v = 0.162695 /0.495
v = 0.329m/s
<em>Hence their velocities after collision is 0.329m/s in the positive x direction</em>
<em></em>
The ratio of the speed of light v in a medium to the speed of light in a vacuum c is called its Refractive Index n
v/c=n
Different substances have different Refractive Indices (plural of Index). Values are always bigger than 1.
Refractive index of water is 1.33
Refractive index of glass is about 1.4
The broad, slightly dome-shaped volcanoes of Hawaii are sheild volcanoes
