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yan [13]
3 years ago
15

Greg dropped a coin from the h meter tall building. If it takes t seconds to reach the ground, determine the position of the coi

n at the t/2 seconds
Physics
1 answer:
My name is Ann [436]3 years ago
8 0

consider the motion of the coin in vertical direction :

Assuming down direction as positive and top of building as origin

Y₀ = initial position of displacement of the coin at the top of building = 0 m

Y = final position of displacement of the coin as it hits the ground = h

t = time taken to hit the ground

a = acceleration = acceleration due to gravity = g

v₀ = initial velocity at the top of the building = 0 m/s

using the equation

Y = Y₀ +  v₀ t + (0.5) a t²

h = 0 + 0 t + (0.5) g t²

h = (0.5) g t²                                                 eq-1


consider the motion of the coin for time "t/2"

Y₀ = initial position of displacement of the coin at the top of building = 0 m

Y' = final position of the coin after time "t/2"

t' = time of travel = t/2

a = acceleration = acceleration due to gravity = g

v₀ = initial velocity at the top of the building = 0 m/s

using the equation

Y' = Y₀ +  v₀ t' + (0.5) a t'²

Y' = 0 + 0 t + (0.5) g (t/2)²

Y' = (0.5) gt²/4

using eq-1

Y' = h/4                           since h = (0.5) g t²


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Answer:

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Explanation:

We can use Bragg's Law's equation to solve this problem. The Bragg's Law's equation is written as follows:

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d = distance between the planes of crystal = 3.5 x 10⁻¹⁰ m

θ = strike angle of waves on plane = 22°

Therefore, substituting the respective values in the equation, we get:

(1)λ = (2)(3.5 x 10⁻¹⁰ m)(Sin 22°)

<u>λ = 2.62 x 10⁻¹⁰ m = 0.262 nm</u>

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3 years ago
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natka813 [3]

Answer:

Take the measurement of the distance (d) with a meter rule (in meters) and also measure the time (t) of the travel in seconds with a stopwatch.

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Answer:

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The relationship between the masses of the object and the gravitational force between them is a direct relationship

Explanation:

The gravitational force between two objects is given by  the equation:

F=G\frac{m_1 m_2}{r^2}

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We observe that:

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Learn more about gravitational force here:

brainly.com/question/1724648

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3 years ago
What is kepler's law??​
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<h2>QUESTION:- </h2>

➜what is kepler's law??

\huge\red{\boxed{\huge\mathbb{\red A \pink{N}\purple{S} \blue{W}\orange{ER}}}}

Kepler gave the three laws or theorems of motion of the orbitals bodies

{\huge {\bold{ \red{ \star}}}}{ \blue{ \bold{FIRST \: \: \: LAW}}}

This law state that the celestial bodies revolves around the stars in elliptical orbit and star as a single focus.

Example :- Earth revolves around the Sun as assuming it as single focus

This also shows that earth revolves around the sun in elliptical orbit.

{\huge {\bold{ \blue{ \star}}}}{ \green{ \bold{SECOND \: \: \: LAW}}}

Area covered by the planet is equal in equal duration of time irrespective of the position of the planet.

It also states that Angular momentum is constant

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\frac{ \triangle \: A}{ \triangle \: T} = \frac{L}{2m}△T△A=2mL

where:-

A is the area.

T is the time.

L is the angular momentum.

M is the mass of the body.

{\huge {\bold{ \green{ \star}}}}{ \purple{ \bold{THIRD \: \: \: LAW}}}

square of the time of the revolution is directly proportional to the cube of the distance between the planet and star in Astronomical unit.

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