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Alecsey [184]
2 years ago
14

A trampoline spring has a force constant k = 800 N/m and is stretched exactly 17.5cm. What is the energy required to do this?

Physics
1 answer:
Artist 52 [7]2 years ago
6 0

Answer:

the energy required for the extension is 12.25 J

Explanation:

Given;

force constant of trampoline spring, k = 800 N/m

extension of trampoline spring, x = 17.5 cm = 0.175 m

The energy required for the extension is calculated as;

E = ¹/₂kx²

E = 0.5 x 800 x 0.175²

E = 12.25 J

Therefore, the energy required for the extension is 12.25 J

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Read 2 more answers
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Answer:

a)1396.52 N

b)1396.52 N

c)a_{satellite}= 3.13 m/sec^2

d)a_{earth}=2.32\times10^{-22} m/s^2

Explanation:

The force experienced by the satelite is giveb by

F= \frac{Gm_{satellite}m_{earth}}{r^2} \\

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now putting values we get

F= \frac{6.67\times10^{-11}(445)(6\times10^24)}{(1.77\times6.38\times10^6)^2}

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a_{earth}= \frac{F}{m_{earth}}

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3 years ago
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Answer:

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