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sveticcg [70]
3 years ago
11

Rewrite the given equation so there is a single power of 5,000 on each side. then, set the exponents equal to each other.

Mathematics
2 answers:
leonid [27]3 years ago
7 0

Second part of this question is no solution

IRISSAK [1]3 years ago
3 0

Answer:

Option a is correct.

2 = 1

Step-by-step explanation:

Using exponent rules:

\frac{1}{a^n} = a^{-n}

a^n \cdot a^m = a^{n+m}

Given the equation:

(\frac{1}{5000})^{2z} \cdot (5000)^{2z+2} = 5000

then;

(5000)^{-2z} \cdot (5000)^{2z+2} = 5000

Apply the exponent rules:

(5000)^{-2z+2z+2} = 5000

then;

(5000)^{-2z+2z+2} = (5000)^1

On comparing both sides we have;

-2z+2z+2 = 1

Combine like terms;

2 = 1

Therefore, the equation shows the result is, 2 = 1

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1 + 1 = A 4 B 37 C 69 D. i. c. k
Shkiper50 [21]

Answer:

It is 2

Step-by-step explanation:

3 0
2 years ago
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6 more than a number w is 2
never [62]

Given a number w, six more than that number is w+6. If you want this result to be 2, you have

w+6=2

Subtract 6 from both sides to get

w = 2-6=-4

3 0
3 years ago
If v varies directly as w, and v=24 when w= 8, find the equation that relates v and w
Zigmanuir [339]

Answer:

v=3w

Step-by-step explanation:

v∝w

v=kw

24=8k

k=24/8 = 3

equation connecting v and w is

v=3w

5 0
3 years ago
What is the remainder of 244 divided by 7?
vlada-n [284]
I think that the correct answer would be 6.

I hope that this helps you !
6 0
3 years ago
Read 2 more answers
Which one is right ???????
wel
Neither, you just multiply the numerators to get 1, then multiply the denominators to get 6. It is 1/6
3 0
3 years ago
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