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QveST [7]
3 years ago
6

Part B: The length of rod PR is adjusted to 17 feet. If width PQ remains the same, what is the approximate new height QR of the

scaffold? Round your answer to the nearest hundredth. Show all your work. (5 points)

Mathematics
2 answers:
Roman55 [17]3 years ago
7 0

Answer:

9.64ft

Step-by-step explanation:

Since the diagram tends to form...a right angled triangle....;

with PR = 17ft...,PQ = 14ft

then to calculate the length of QR

we use the pythagoras theorem...which is only applicable to right angled triangles

PR^2 = PQ^2 + QR^2

(17)^2 = (14)^2 + QR^2

where we make QR the subject of formula;

QR^2 = (17)^2 - (14)^2

QR = square root of( 289 - 196)

QR = square root of( 93)

;Therefore the length of QR = 9.64ft

Alenkinab [10]3 years ago
5 0

Answer:

9.64ft

Step-by-step explanation:

Since the diagram tends to form...a right angled triangle....;

with PR = 17ft...,PQ = 14ft

then to calculate the length of QR

we use the pythagoras theorem...which is only applicable to right angled triangles

PR^2 = PQ^2 + QR^2

(17)^2 = (14)^2 + QR^2

where we make QR the subject of formula;

QR^2 = (17)^2 - (14)^2

QR = square root of( 289 - 196)

QR = square root of( 93)

;Therefore the length of QR = 9.64ft

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