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3241004551 [841]
3 years ago
13

A "8" grams box is pushed with a force of 100 N for 1m whereas opposing force is 10 N. A) Find the net work done on the box. B)

Find the total work done by considering work done by each force. "
Physics
1 answer:
Debora [2.8K]3 years ago
8 0

Answer:

A)   Wn = 90J

B)   W1 = 100J

     W2 = 10J

Explanation:

A) The net work done on the box is calculated by using the following formula:

W_n=(F_1-F_2)d     (1)

F1 = 100N

F2 = 10N

d: distance on which the box is moved = 1m

You replace the values of the parameters in the equation (1):

W_n=(100N-10N)(1m)=90J

The net work on the box is 90J

B) The total work done by each force is:

W_1=F_1d=(100N)(1m)=100J\\\\W_2=F_2d=(10N)(1m)=10J

The first box does a work of 100J and the second force does a force of 10J

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two workers are sliding 260 kg crate across the floor. one worker pushes forward on the crate with a force of 450 n while the ot
balu736 [363]

To find out the kinetic friction, using the coefficient friction formula.

What is kinetic friction?

A force that acts between moving surfaces is called "kinetic friction." A force acting in opposition to the direction of a moving body on the surface is felt. The two materials' kinetic friction coefficients will determine how much force is applied.

What is coefficient friction?

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UK

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Using UK

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brainly.com/question/14111192

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A polar bear runs at a speed of 11 m/s and has a mass of 380.2 kg. How much Kinetic energy does the bear have?
Yanka [14]

Answer:

\boxed{\sf Kinetic \ energy \ of \ the \ bear (KE) = 23002.1 \ J}

Given:

Mass of the polar bear (m) = 6.8 kg

Speed of the polar bear (v) = 5.0 m/s

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Explanation:

Formula:

\boxed{ \bold{\sf KE =  \frac{1}{2} m {v}^{2} }}

Substituting values of m & v in the equation:

\sf \implies KE =  \frac{1}{2}  \times 380.2 \times  {11}^{2}

\sf \implies KE = \frac{1}{ \cancel{2}}  \times  \cancel{2} \times 190.1 \times 121

\sf \implies KE = 190.1 \times 121

\sf \implies KE = 23002.1 \: J

\therefore

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True,
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