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Helen [10]
3 years ago
9

A torque of 50 N*m acts on a wheel of moment of inertia 25 kg*m^2 for 4 s and then is removed.

Physics
1 answer:
motikmotik3 years ago
3 0
You have to find the calculate<span> the circumference first then you can just multiply the diameter by π, which is about 3.142. That gives you the distance for each </span>revolution<span>. Then you can multiply by the </span>number of revolutions<span> per minute.

</span>
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An astronaut has left the International Space Station to test a new space scooter. Her partner measures the following velocity c
KiRa [710]

Acceleration can be defined as the change of speed in an instant of time, that is

a = \frac{v_f-v_i}{\Delta t}

Here,

v_f = Final velocity

v_i = Initial velocity

\Delta t = Change in time

From this expression we will calculate the requested values replacing the variables in each of the given terms

PART A) The values under this condition are:

v_f = 5.3m/s

v_i = 15m/s

\Delta t = 10.4s

Replacing,

a = \frac{5.3m/s-(15m/s)}{10.4s}

a = -0.93m/s^2

PART B ) The values under this condition are:

v_f = -15m/s

v_i = -5.3m/s

\Delta t = 10.4

Replacing,

a = \frac{-(15m/s)-(-5.3m/s)}{10.4s}

a = -0.93m/s^2

Therefore the acceleration in the second time interval is -0.93m/s^2

PART C) The values under this condition are:

v_f = -15m/s

v_i = 15m/s

\Delta t = 10.4

Replacing,

a = \frac{-15m/s-(15m/s)}{10.4s}

a = -2.9m/s^2

6 0
3 years ago
1. A signal source has an open-circuit voltage of 1V, and a short-circuit current of10mA. What is the source resistance
LiRa [457]

Answer:

100 Ω

Explanation:

Given that

Open circuit voltage, V = 1 V

Short circuit current, I = 10 mA

Source resistance R, = ?

This is rather a straight forward question. Remember Ohms Law? Current being directly proportional to the voltage and inversely proportional to the resistance?

Yeah, that's the formula we'd be using.

Ohms Law states that V = IR, and thus, if we make R subject of the formula, we have

R = V / I, on substituting the values, we have

R = 1 / 10*10^-3

R = 1 / 0.01

R = 100 Ω

8 0
3 years ago
A parallel-plate capacitor has plates of area A. The plates are initially separated by a distance d, but this distance can be va
makkiz [27]

Answer:

a) In a parallel plate capacitor the capacitance is

C = \frac{Q}{V} = \epsilon_0\frac{A}{d}

So, in order to halve the capacitance the plate separation should be twice the original distance.

b) Same question as (a).

c) According to the above equations, the charge stored in a capacitor is directly proportional to the plate separation.

\frac{Q}{V} = \frac{A}{d}

In order to halve the charge stored the plate separation should be half the original distance.

d) Same question as (c).

e) The energy stored in a capacitor is

U = \frac{1}{2}CV^2 = \frac{1}{2}\epsilon_0\frac{A}{d}(Ed)^2 = \frac{1}{2}\epsilon_0AE^2d

In order to halve the energy stored in the capacitor, the plate separation should be twice the original distance.

f) Same question as (e).

g) The energy density is given by the following equation

u = \frac{\frac{1}{2}CV^2}{Ad} = \frac{\frac{1}{2}\epsilon_0\frac{A}{d}(E^2d^2)}{Ad} = \frac{1}{2}\epsilon_0E^2.

As it turns out, the energy density is independent from the geometric factors. This makes sense, because the electric field in a parallel field capacitor is independent from the distance.

3 0
3 years ago
What are the types of energies released when a candle burns?
Phantasy [73]
When a candle is burning the candle is releasing thermal and radiant energy
4 0
3 years ago
Read 2 more answers
A metal wire has a resistance of 13.00 at a temperature of 25.0 degree celsius
Nady [450]

Explanation:

what exactly are you asking for?

4 0
2 years ago
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