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IRINA_888 [86]
3 years ago
14

Investigators are working on a case where they need to know whether a watch will stop when it is dropped. In order to have a ver

ified or reliable answer to this question, what should they do?
Call the manufacturer to ask whether it will stop under these circumstances
Drop a similar watch multiple times and record the results
Consult with more senior forensic scientists for their experiences
Take the watch apart and test the mechanism to see what causes failure
Physics
2 answers:
ivanzaharov [21]3 years ago
6 0

In order to have a verified or reliable answer to this question, they should take the watch apart and test the mechanism to see what causes failure.

Answer: Option D

<u>Explanation: </u>

For dropping a similar watch to record results, we need to buy another one. So, it becomes expensive. And, calling the manufacturer will give accurate results, but no knowledge. It is like getting multiple choices by luck.

Consulting senior faculty won’t result in any progress, because they may not have conducted these. So, one should rip off the watch, and study the mechanism, and its limitations.  The testing of mechanism gives the actual results.

vredina [299]3 years ago
5 0

Answer: B) Drop a similar watch multiple times and record the results.

Explanation:

In order to have a verified or reliable answer to this question, investigators must drop a similar watch multiple times and record the results. By doing this and repeatedly getting the same result(s), they are able to determine that their answer is in fact true.

***<em> I would also like to note that I got this question right on a test. Cheers!</em>

You might be interested in
A generator delivers an AC voltage of the form Δv =(82 V) sin (75πt) to a capacitor. Themaximum current in the circuit is 1.00A.
Cloud [144]

Answer:

1. 57.99V

2. 37.5Hz

3. 0.7072A

4. 82 ohms

5. 5.18x10^-5F

Explanation:

In answer to this question, we have the Standard equation of AC emf to be

V = V0 x sin ωt

We have

V0 = 82V,

ω = 75π

1.

RMS Voltage =

V0/√2 = 82 /√2

= 82/1.414

= 57.99V

2.

ω = 2π* f

75π = 2πf

Frequency,f = 75π/2π

= 235.5/6.28

= 37.5 Hz

3.

RMS current

= Imax/√2

= 1.00/1.414

= 0.7072A

4.

Reactance

= Vrms/ Irms

= 57.99/0.7072

= 81.999

= 82.0 Ω

5.

Reactance = 1/ ω x C

Reactance = 82

ω = 75π

We put these values into the equation above and make c the subject of the formula

C = 1/82.0 x 75π

C = 1/ 82.0 x 75 x 3.14

C = 1/19311

Capacitance = 5.18x10^-5F

6 0
3 years ago
Focal Lengths II If you were handed an unmarked convex lens (no optical track) and asked to estimate its focal length quickly, h
Lapatulllka [165]

Answer:

Explanation:

To estimate the focal length of a convex lens follow the following steps.

1. take a convex lens.

2. Stand near a window which is just opposite to a wall.

3. Look at a tree which is far away from the window by the convex lens.

4. focus the image of the tree on the wall which is opposite to the window.

5. You wll observe that by changing the position of convex lens a sharp and inverted and small image is seen on the wall.

5. Now measure the distance between the lens and the wall.

7. This distance is the rough focal length of the convex lens.

5 0
3 years ago
What is the current produced by the solar cells of a pocket calculator through which 4.00 C of charge passes in 4.00 hr? Give yo
AfilCa [17]

The average current passing through a device is given by:

I = Q/Δt

I is the average current

Q is the amount of charge that has passed through the device

Δt is the amount of elapsed time

Given values:

Q = 4.00C

Δt = 4.00hr = 14400s

Plug in the values and solve for I:

I = 4.00/14400

I = 0.000277777778A

I = 0.278mA

3 0
3 years ago
HELP ODYSSEY WARE !! WILL REWARD BRAINLIEST!
noname [10]

Answer:

98,000 J

Explanation:

The formula for gravitational potential energy is mgh, where m is the mass in kilograms of the object, g is the acceleration due to gravity, and h is the height in meters. Therefore, since the gravity here is 9.8 m/s^2, the potential energy of that object would be 5*9.8*2000=98,000 J. Hope this helps!

5 0
3 years ago
An engine extracts 441.3kJ of heat from the burning of fuel each cycle, but rejects 259.8 kJ of heat (exhaust, friction,etc) dur
KengaRu [80]

Answer:

\eta = 0.411

Explanation:

As we know that efficiency is defined as the ratio of output useful work and the input energy to the engine

So here we know that the

input energy = 441.3 kJ

energy rejected = 259.8 kJ

so we have

Q_1 - Q_2 = W

W = 441.3 kJ - 259.8 kJ = 181.5 kJ

now efficiency is defined as

\eta = \frac{W}{Q_1}

\eta = \frac{181.5}{441.3}

\eta = 0.411

8 0
3 years ago
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