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Nata [24]
3 years ago
13

If triangle ABC is a triangle with m∠C = 90°, which of the following must be true about angles A and B?

Mathematics
1 answer:
blsea [12.9K]3 years ago
7 0
A and B are complimentary angles
it means :
A +B = 90

hope this helps
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Y=(x-4)(x+20) find vertex
andrew11 [14]
Y = (x-4)(x+20)   ===> 0 = (x-4)(x+20)

that means the roots of that quadratic are x = 4 and x = -20.

now, the vertex will be between these two guys, right in between.

from -20 to 4 there are 24 units, half-way of that is 12 units, so, if we move from -20, 12 units to the right or towards 4, we'll end up at -20 + 12 = -8.

so, the vertex's x-coordinate is -8 then, what's "y" anyway?

y = (x-4)(x+20)         x = -8

y = [(-8) - 4] [(-8) + 20]

y = (-12) ( 12)

y = -144

therefore, the vertex is at (-8 , -144)
7 0
4 years ago
I dont know any of this-
artcher [175]

Answer: the answer is c

Step-by-step explanation:

3 0
3 years ago
Use the image below to answer the following question. Find the value of sin x° and cos y°. What relationship do the ratios of si
postnew [5]

Step-by-step explanation:

sinx=5/13

cosy=5/13

RELATIONSHIP

they are equal to one another

OR

sinx=cosy

3 0
3 years ago
Select all that are undefined. sec (45°) csc (0°) sec (90°)
Murrr4er [49]

Answer:

csc (0°) and sec (90°) are not defined.

Step-by-step explanation:

Given the options wehave to select the option which is undefinesd

First option: sec 45°

sec45^{\circ}=\frac{1}{cos(45^{\circ})}=\frac{1}{\frac{1}{\sqrt2}}=\sqrt2

which is defined

Second option: csc(0°)

csc(0^{\circ})=\frac{1}{sin0}=\frac{1}{0}=\infty

which is not defined

Third option: sec(90°)

sec(90^{\circ})=\frac{1}{cos(90)}=\frac{1}{0}=\infty

which is not defined.

Hence, option 2 and 3 are not defined.

3 0
3 years ago
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DENIUS [597]

Answer:

2/6

3/9

4/12

Step-by-step explanation:

3 0
3 years ago
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