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alisha [4.7K]
3 years ago
9

If an instrument has 10 ml td +/- 0.01 ml written on it, the user should ..... question 5 options: record 10 ml in the notebook

after using it. record 10.0 ml in the notebook after using it. record 10.00 ml in the notebook after using it. record 5.00 ml in the notebook after using it.
Chemistry
1 answer:
galina1969 [7]3 years ago
6 0

Answer : The correct option is "record 10.00 ml in the notebook after using it."

Explanation :

If an instrument has "10 mL TD" written on it, that means the instrument is meant To Deliver (TD) 10 mL of volume.

Therefore the option that has 5.00 mL is not correct.

"+/- 0.01 mL" indicates the precision of the instrument. We know that no measurement is 100% accurate and there is always some uncertainty associated with any measurement.

Here, 0.01 indicates the uncertainty in the measurement.

When we have 0.01 mL , that means the instrument can record precisely to the hundredths place.

The more the significant figures, the greater is the accuracy of the measurement.

Therefore when we use an instrument that has "+/- 0.01 mL" written on it, we should record the reading as 10.00 mL  


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Which type of weathering helped to form barrier islands
Grace [21]

Barrier islands typically have sand in the beach zone and dune field, and mud in the back-barrier. Overwash deposits sand in the back-barrier.

Barrier islands form in three ways. They can form from spits, from drowned dune ridges or from sand bars. Longshore drift is the movement of sand parallel to the shore caused by the angle of the waves breaking on the beach. ... When a storm such as a hurricane digs an inlet through the spit a barrier island is formed.

7 0
3 years ago
We make a basic solution by mixing 50. mL of 0.10 M NaOH and 50. mL of 0.10 M Ca(OH)2. It requires 250 mL of an HCl solution to
andreyandreev [35.5K]

<u>Answer:</u> The correct answer is Option 5.

<u>Explanation:</u>

  • To calculate the molarity of the solution after mixing 2 solutions, we use the equation:

M=\frac{n_1M_1V_1+n_2M_2V_2}{V_1+V_2}

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of the NaOH.

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of the Ca(OH)_2

We are given:

n_1=1\\M_1=0.10M\\V_1=50mL\\n_2=2\\M_2=0.1\\V_2=50mL  

Putting all the values in above equation, we get:

M=\frac{(1\times 0.1\times 50)+(2\times 0.1\times 50)}{50+50}\\\\M=0.15M

  • To calculate the molarity of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base.

We are given:

n_1=1\\M_1=?M\\V_1=250mL\\n_2=1\\M_2=0.15M\\V_2=100mL

Putting values in above equation, we get:

1\times M_1\times 250=1\times 0.15\times 100\\\\M_1=0.06M

Hence, the correct answer is Option 5.

7 0
3 years ago
What would be the molarity of a solution in which 0.56 mole of NaCl is dissolved in enough water to make 2.7 L of solution?
yan [13]

Answer:

Molarity = 0.21 M

Explanation:

Moles <em>solute </em>(mol) = Volume <em>solution</em> (L) x Molarity <em>solution </em>(M)

0.56 mol NaCl = 2.7 L x M

M = 0.2074074074

5 0
2 years ago
Suppose 6.63g of zinc bromide is dissolved in 100.mL of a 0.60 M aqueous solution of potassium carbonate. Calculate the final mo
Alenkasestr [34]

Answer:

[Zn²⁺] = 4.78x10⁻¹⁰M

Explanation:

Based on the reaction:

ZnBr₂(aq) + K₂CO₃(aq) → ZnCO₃(s) + 2KBr(aq)

The zinc added produce the insoluble ZnCO₃ with Ksp = 1.46x10⁻¹⁰:

1.46x10⁻¹⁰ = [Zn²⁺] [CO₃²⁻]

We can find the moles of ZnBr₂ added = Moles of Zn²⁺ and moles of K₂CO₃ = Moles of CO₃²⁻ to find the moles of CO₃²⁻ that remains in solution, thus:

<em>Moles ZnB₂ (Molar mass: 225.2g/mol) = Moles Zn²⁺:</em>

6.63g ZnBr₂ * (1mol / 225.2g) = 0.02944moles Zn²⁺

<em>Moles K₂CO₃ = Moles CO₃²⁻:</em>

0.100L * (0.60mol/L) = 0.060 moles CO₃²⁻

Moles CO₃²⁻ in excess: 0.0600moles CO₃²⁻ - 0.02944moles =

0.03056moles CO₃²⁻ / 0.100L = 0.3056M = [CO₃²⁻]

Replacing in Ksp expression:

1.46x10⁻¹⁰ = [Zn²⁺] [0.3056M]

<h3>[Zn²⁺] = 4.78x10⁻¹⁰M</h3>

4 0
3 years ago
Balance each reaction and write its reaction quotient, Qc:(b) POCl₃(g) ⇄ PCl₃(g) + O₂(g)
Komok [63]

When we balance the given equation

      POCl₃(g) ⇄ PCl₃(g) + O₂(g)

We will get

      2POCl₃(g) ⇄ 2PCl₃(g) + O₂(g)

Solution:

Balancing the given equation

      POCl₃(g) ⇄ PCl₃(g) + O₂(g)

Balancing the number of O

      2POCl₃(g) ⇄ PCl₃(g) + O₂(g)

Balancing the number of P and Cl

      2POCl₃(g) ⇄ 2PCl₃(g) + O₂(g)

We get the balanced equation

      2POCl₃(g) ⇄ 2PCl₃(g) + O₂(g)

The reaction quotient will be

     Qc = [product] / [reactant]

     Qc ​= [PCl₃(g) + O₂(g)] / [POCl₃(g) ]

To learn more click the given link

brainly.com/question/26227625

#SPJ4

4 0
1 year ago
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