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Licemer1 [7]
2 years ago
10

Arrange the steps typically followed in the data preparation process in the order of occurrence. (Place the first step at the to

p.)
Chemistry
1 answer:
Pavel [41]2 years ago
3 0

Data validation → editing data → entry data → tabulation

This enables better integration, consumption and analysis of larger datasets using advanced business intelligence with analytics solutions.

<h3>What is data preparation ?</h3>

Data collection, combination, structure, and organisation are all steps in the process of preparing data for use in business intelligence (BI), analytics, and data visualisation applications.

  • Data prep is a common colloquial term for data preparation. It is also referred to as "data wrangling," while other professionals use that phrase more specifically to mean "cleaning, structuring, and transforming data." This usage distinguishes data wrangling from the data pretreatment stage.

Learn more about Data preparation here:

brainly.com/question/28056387

#SPJ4

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A plant uses energy from the sun to make food what kind of energy transformation is this
IRISSAK [1]

Answer:

photosynthesis

Explanation:

bsbsbsns

5 0
4 years ago
A chemical reaction takes place inside a flask submerged in a water bath. The water bath contains 8.10kg of water at 33.9 degree
lions [1.4K]

Answer:

The new temperature of the water bath 32.0°C.

Explanation:

Mass of water in water bath ,m= 8.10 kg = 8100 g ( 1kg = 1000g)

Initial temperature of the water = T_1=33.9^oC=33.9+273K=306.9 K

Final temperature of the water = T_2

Specific heat capacity of water under these conditions =  c = 4.18 J/gK

Amount of energy lost by water = -Q = -69.0 kJ = -69.0 × 1000 J

( 1kJ=1000 J)

Q=m\times c\times \Delta T=m\times c\times (T_2-T_1)

-69.0\times 1000 J=8100 g\times 4.18 J/g K\times (T_2-306.9 K)

-69,000.0 J=8100 g\times 4.18 J/g K\times (T_2-306.9 K)

T_2=304.86 K=304.86 -273^oC=31.86^oC\approx 32.0^oC

The new temperature of the water bath 32.0°C.

5 0
4 years ago
Volume of water displaced = 0.175 L Mass g Density g/cm3 Hardness: = Determine the unknown mineral. Unknown mineral: 7​
erastovalidia [21]

Answer:

Mass: 981.0 g

Density: 5.61 g/cm^3

Hardness: = 2.5 - 3

Unknown material: Chalcocite

Explanation:

5 0
3 years ago
What is the affect of neutrons on atoms
Evgen [1.6K]

Answer:

It's better to explain it.

Explanation:

Neutrons do not affect the electron configuration, but the sum of atomic number and the number of neutrons, or neutron number, is the mass of the nucleus. You know that neutrons are found in the nucleus of an atom. Under normal conditions, protons and neutrons stick together in the nucleus. During radioactive decay, they may be knocked out of there. Neutron numbers are able to change the mass of atoms, because they weigh about as much as a proton and electron together. if your asking What is the role of a neutron in an atom? then, Neutrons are very important in providing stability for an atom. Some atoms don't "need" neutrons - The hydrogen atom does not have any neutrons. However, as the atomic number ( # of protons ) increases, the number of neutrons increases as well.

Protons don't like each other. Naturally, 'positive charges repel', so it wouldn't be possible to have more than one proton in the nucleus. Here's where the neutron comes in.

Hope this helps. :)

7 0
4 years ago
State what would be observed when the following pairs of reagents are mixed in a test tube.
Mandarinka [93]

Answer:

(i). C6H2COOH and Na2CO3(aq)

observation: <u>Bubbles</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>colourless</u><u> </u><u>gas</u><u> </u><u>(</u><u>carbon</u><u> </u><u>dioxide</u><u> </u><u>gas</u><u>)</u>

(ii) CH3CH2CH2OH and KMnO4 /H

observation: <u>The</u><u> </u><u>orange</u><u> </u><u>solution</u><u> </u><u>turns</u><u> </u><u>green</u><u>.</u>

[<em>This</em><em> </em><em>is</em><em> </em><em>because</em><em> </em><em>oxidation</em><em> </em><em>of</em><em> </em><em>propanol</em><em> </em><em>to</em><em> </em><em>propanoic</em><em> </em><em>acid</em><em> </em><em>occurs</em>]

(iii) CH3CH2OH and CH3COOH + conc. H2SO4

observation: <u>A</u><u> </u><u>sweet</u><u> </u><u>fruity</u><u> </u><u>smell</u><u> </u><u>is</u><u> </u><u>formed</u><u>.</u>

[<em>This</em><em> </em><em>is</em><em> </em><em>because</em><em> </em><em>an</em><em> </em><em>ester</em><em>,</em><em> </em><em>diethylether</em><em> </em><em>is</em><em> </em><em>formed</em><em>]</em>

(iv) CH3CH = CHCH3 and Br2 /H2O

observation: <u>a</u><u> </u><u>brown</u><u> </u><u>solution</u><u> </u><u>is</u><u> </u><u>formed</u><u>.</u>

4 0
3 years ago
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