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Studentka2010 [4]
1 year ago
10

While finding the number of molecules of oxygen molecules present in 3.65 moles of Na2SO4 the conversion factor used would be

Chemistry
1 answer:
zvonat [6]1 year ago
8 0

Answer

Avogadro's number: One mole of any substance contains 6.022×10²³ molecules

Explanation

While finding the number of moles of oxygen molecules present in 3.65 moles of Na2SO4 the conversion factor used would be Avodagro's number, which is

One mole of any substance contains 6.022×10²³ molecules.

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Aspirin has a formula c9h8o4. what is the molar mass of aspirin? 1. 95 g 2. 220 g 3. 180 g 4. 325 g
Debora [2.8K]
Molar mass is the mass of 1 mol of substance.
Molar masses of compounds can be calculated by the sum of the products of molar masses of individual atoms by number of corresponding individual atoms.
Compound formula is C₉H₈O₄
the molar masses of the atoms making up the compound 
C - 12 g/mol x 9  C  = 108 
H - 1 g/mol x 8 H = 8 
O - 16 g/mol x 4 O = 64
therefore molar mass of aspirin = 108 + 8 + 64 = 180 g/mol
answer is 3.180 
5 0
3 years ago
Write a balanced equation for the following neutralization reaction HBr+LiOH<->
Sophie [7]

Answer:

HBr(aq) + LiOH(aq) = LiBr(aq) + H2O(l)

Explanation:

For this reaction, the reactants are the hydrobomic acid and the lithium hydroxide which produces the products lithium bromide and water.

8 0
3 years ago
Please help. It's for chemistry
irinina [24]
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3 0
2 years ago
What is the name for the formula C5O10?
Natalija [7]

Propylethylene would be the answer

8 0
3 years ago
Read 2 more answers
2. Write the chemical equations for the neutralization reactions that occurred when HCL and NaOH were added to the buffer soluti
lutik1710 [3]

Answer:

HCI(aq)+CH3COONa(s) ----> CH3COOH(aq)+NaCl(s)

NaOH(aq)+CH3COOH(aq) ----> CH3COONa(s)+H2O(l)

Explanation:

A buffer is a solution that resists changes in acidity or alkalinity. A buffer is able to neutralize a little amount of acid or base thereby maintaining the pH of the system at a steady value.

A buffer may be an aqueous solution of a weak acid and its conjugate base or a weak base and its conjugate acid.

The equations for the neutralizations that occurred upon addition of HCl or NaOH are;

HCI(aq)+CH3COONa(s) ----> CH3COOH(aq)+NaCl(s)

NaOH(aq)+CH3COOH(aq) ----> CH3COONa(s)+H2O(l)

5 0
3 years ago
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