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Studentka2010 [4]
1 year ago
10

While finding the number of molecules of oxygen molecules present in 3.65 moles of Na2SO4 the conversion factor used would be

Chemistry
1 answer:
zvonat [6]1 year ago
8 0

Answer

Avogadro's number: One mole of any substance contains 6.022×10²³ molecules

Explanation

While finding the number of moles of oxygen molecules present in 3.65 moles of Na2SO4 the conversion factor used would be Avodagro's number, which is

One mole of any substance contains 6.022×10²³ molecules.

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In standardizing a naoh solution a student found that 25.55cm of base neutralize exactly 21.35cm of 0.12M HCl find the molarity
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Answer:

O.1M

Explanation:

First let's generate a balanced equation for the reaction

NaOH + HCl —>NaCl + H2O

From the equation,

The ratio of the acid to base is 1:1.

From the question, we obtained the following:

Ma = Molarity of acid = 0.12M

Va = volume of acid = 21.35cm3

Vb = volume of base = 25.55cm3

Mb = Molarity of base =?

We obtained nA(mole of acid) and nB(mole of base) to be 1

The molarity of the base can be calculated for using:

MaVa/ MbVb = nA / nB

0.12x21.35 / Mb x 25.55 = 1

Cross multiply to express in linear form

Mb x 25.55 = 0.12x21.35

Divide both side by 25.55

Mb = (0.12x21.35) / 25.55

Mb = 0.1M

The molarity of the base is 0.1M

6 0
2 years ago
How to use molar mass
ruslelena [56]

Explanation:

the molar mass of a compound can be caucaleted by adding the standar atomic masses.

8 0
3 years ago
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A certain half-reaction has a standard reduction potential +0.80 V . An engineer proposes using this half-reaction at the anode
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Answer:

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b. There is no maximum.

Explanation:

We can solve this question by remembering that the cell potential is given by the formula

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Now the problem states the cell must provide at least 0.9 V and that the reduction potential of the  oxidized species  0.80 V, thus

ε⁰ reduction -  ε⁰  oxidation ≥  ε⁰ cell

Since ε⁰  oxidation is by definition the negative of ε⁰ reduction , we have

ε⁰ reduction - ( 0.80 V )  ≥  0.90 V

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Therefore,

(a) The minimum standard reduction potential is 1.70 V

(b) There is no maximum standard reduction potential since it is stated in the question that we want to have a cell that provides at leat 0.9 V

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3 years ago
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Answer: An axis.

Explanation:

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aspirin C6H4(CO2)(CO2CH3),can be prepared in the chemistry laboratory by the reactions of salicylic acid, C6H4(CO2H)(OH),with ac
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262mol 1=kg
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