Question

The diagram below shows a set of three different sized containers tanner used for storing dry goods. The largest container held 12 3/4 cups of dry goods.
Container A : 2/3 of the amount in container A
Container B: 2/3 of the amount in container B
Container C: ???
What was the total amount In cups,of dry goods that tanner could store in all three containers ?
Show your work
How many cups

Answer 1

Answer:

The total amount was $14\frac{1}{12}$

Step-by-step explanation:

Container A contains $\frac{2}{3}$ cups

Container B contains $\frac{2}{3}$ cups

It is given that the largest container held $12 \frac{3}{4}$ cups

Since $12 \frac{3}{4}$ > $\frac{2}{3}$,

Container C should contain $12 \frac{3}{4}$ cups of dry goods.

So, total amount in cups stored in all three containers = $\frac{2}{3} +\frac{2}{3} +12\frac{3}{4}$

= $\frac{8}{12} +\frac{8}{12} +\frac{9}{12} +12$

= $\frac{25}{12} +12$

= $2\frac{1}{12} +12$

= $14\frac{1}{12}$

Answer 2

2/3 plus 2/3 is 4/3 or 16/12

we have 12 and 9/12 subtracted by 16/12 thats is the answer

11 7/12 :)