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ollegr [7]
3 years ago
15

What’s the correct why to solve

Mathematics
1 answer:
Vaselesa [24]3 years ago
6 0

x^2-y^2=2\\ \underline{x^2+y^2=4}\\\\ 2x^2=6\\ x^2=3\\ x=-\sqrt3 \vee x=\sqrt3\\\\ 3+y^2=4\\ y^2=1\\ y=-1 \vee y=1\\\\ x\in\{(-\sqrt3,-1),(-\sqrt3,1),(\sqrt3,-1),(\sqrt3,1)\}

So, there are 4 solutions.

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PLEASE HELP !! ILL GIVE BRAINLIEST *EXTRA 40 POINTS* DONT SKIP :(( .!
Llana [10]

Define your two QUESTIONS

Write your system of EQUATIONS

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Find the SOLUTION to the question being asked.

6 0
3 years ago
Help me please thanks !
GREYUIT [131]
That’s 125 times 9!!! which is 1125!!!
4 0
3 years ago
Huxian's father gives her $120 as her monthly allowance. a) If she spends an average of 5 dollars a day, find the amount on mone
abruzzese [7]

Answer:

3 days=  $105, 6 days= $90, 10 days= $70

Step-by-step explanation:

You can rewrite this equation as y=120-5x

x is the amount of days passed

plug in 3 for x and you get 15. 120-15=105

plug in 6 for x and you get 30. 120-30=90

plug in 10 for x you get 50. 120-50=70

Hope this helps!

:)

4 0
2 years ago
(12. Which of the following is true about the data set {3,5, 5, 7,9}?
liubo4ka [24]

Answer:

A . because on the data set we already have the median then we use range which is max -min

7 0
3 years ago
4/25 of the purchases were stuffed animals. 10/21 of them were bears. What fraction of the purchases were stuffed bears?
Bess [88]
Let's name all the purchases "x"

so \frac{4}{25}of them were stuffed animals, and out of that \frac{10}{21} were bears.

to get the results we have to multiply the fraction of bears by the fraction of the stuff animals:

\frac{4}{25}*\frac{10}{21}.
 
and now we simplify:
\frac{4*2}{5*21}=\frac{8}{105}

and this is the answer!






4 0
3 years ago
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