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ollegr [7]
3 years ago
15

What’s the correct why to solve

Mathematics
1 answer:
Vaselesa [24]3 years ago
6 0

x^2-y^2=2\\ \underline{x^2+y^2=4}\\\\ 2x^2=6\\ x^2=3\\ x=-\sqrt3 \vee x=\sqrt3\\\\ 3+y^2=4\\ y^2=1\\ y=-1 \vee y=1\\\\ x\in\{(-\sqrt3,-1),(-\sqrt3,1),(\sqrt3,-1),(\sqrt3,1)\}

So, there are 4 solutions.

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Question 3 of 10 A Assume EFG = JKL. If mLJ = 90°, mL K = 26°, and m< L = 64°, what is the measure of < E?
kumpel [21]

The measure of angle E will be 90 degrees as well.

Assume EFG = JKL.

If mLJ = 90°, mL K = 26°, and m< L = 64°,

<h3>What is the congruent triangle?</h3>

Two triangles are said to be congruent if the length of the sides is equal, a measure of the angles are equal and they can be superimposed.

We have been given an image of two congruent triangles.

Since, EFG = JKL

therefore, the corresponding angles will be congruent.

m < J = 90° = m< E = 90

By congruence measure of angle, J will be equal to the measure of angle E.

Hence, The measure of angle E will be 90 degrees as well.

Learn more about congruent;

brainly.com/question/10586347

#SPJ1

4 0
2 years ago
A private and a public university are located in the same city. For the private university, 1038 alumni were surveyed and 647 sa
Snezhnost [94]

Answer:

The difference in the sample proportions is not statistically significant at 0.05 significance level.

Step-by-step explanation:

Significance level is missing, it is  α=0.05

Let p(public) be the proportion of alumni of the public university who attended at least one class reunion  

p(private) be the proportion of alumni of the private university who attended at least one class reunion  

Hypotheses are:

H_{0}: p(public) = p(private)

H_{a}: p(public) ≠ p(private)

The formula for the test statistic is given as:

z=\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

  • p1 is the sample proportion of  public university students who attended at least one class reunion  (\frac{808}{1311}=0.616)
  • p2 is the sample proportion of private university students who attended at least one class reunion  (\frac{647}{1038}=0.623)
  • p is the pool proportion of p1 and p2 (\frac{808+647}{1311+1038}=0.619)
  • n1 is the sample size of the alumni from public university (1311)
  • n2 is the sample size of the students from private university (1038)

Then z=\frac{0.616-0.623}{\sqrt{{0.619*0.381*(\frac{1}{1311} +\frac{1}{1038}) }}} =-0.207

Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.  

6 0
3 years ago
Imagine there are 5 cards. They are colored red, yellow, green, white, and black. You mix up the cards and select one of them wi
iragen [17]

Step-by-step explanation:

step one:

given that the sample space is

red, yellow, green, white, and black. i.e (1+1+1+1+1)= 5

the sample size is 5

the probability of picking a colored card at random is

Pr(a colored card)= 1/5

step two:

without replacement, after the first event, the sample size is now 4

then the probability of picking a colored card at random is

Pr(a colored card)= 1/4

5 0
3 years ago
Im throwing tons of points for these questions so please help
Galina-37 [17]

10. x = 4,-4

11.  x = 2,-2

12. Length = 12 yards, Weight = 6 yards

13.  x = -5,2


3 0
3 years ago
Read 2 more answers
??? Answers please.....
Paha777 [63]
The answer to this problem is 8 I believe. I hope you do good





3 0
2 years ago
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