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tester [92]
3 years ago
14

If part of an electric circuit dissipates energy at 6 W when it draws a current of 3 A, what voltage is impressed across it?

Physics
1 answer:
Lena [83]3 years ago
5 0

Answer:2 volts

Explanation:

Power=current x voltage

6=3 x voltage

Divide both sides by 3

6/3=(3 x voltage)/3

2=voltage

Voltage=2volts

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6 0
3 years ago
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An astronaut takes a tuning fork with her to the moon she strikes it inside the cabin the cabin is normally filled with air so t
Lesechka [4]

Answer:

d

Explanation:

a and b: it vibrates in both the difference is whether you hear the sound or not the lack or presence of molecules does not hinder the timing fork from vibrating but can hinder you from hearing since sound is a mechanical wave therefore require a medium bringing us to (c) these vibrations are transmitted because there is presence of a medium i.e air molecules so sound can be heard

but in (c) it is true since the vibrations are created but are not transmitted to your ears due to lack of a medium

4 0
3 years ago
Wind instruments like trumpets and saxophones work on the same principle as the "tube closed on one end" that we examined in our
Grace [21]

Answer:

The correct answer is - low pitch

Explanation:

Now for the case it is mentioned that the tube closed on one end frequency is:

f = v/2l

Where,

l = length of the tube

v = velocity of longitudinal wave of gas filled in the tube

if frequency increases then pitch will be increase as well as pitch depends on frequency.

Now increase with the temperature the density of the gas decreases and velocity v is inversely proportional to density of gas so velocity increases. So if there is an increase in frequency so pitch also increases.

As the temperature inside the house is at 750 F more than outsideat 450 Fso pitch is more inside and the pitch is low outside.

8 0
3 years ago
___Na3P + ___RbF → ___NaF + ___Rb3P
IgorC [24]

Answer:

Na3P + <u>3</u>RbF -> <u>3</u>NaF + Rb3P

3 0
4 years ago
Part 1 :
dybincka [34]

Answer:

1. 218.55 N

2. 30.96^{o}

3. 2.1 m/s^{2}

Explanation:

Part 1;

Net force F=mg sin \theta where m is mass, g is gravitational force and \theta is the angle of inclination

F= 46*9.8*sin 29^{o}= 218.55N

Frictional force, F_{r} is given by

F_{r} = \mu_{s}mg cos \theta where \mu_{s} is the coefficient of static friction

F_{r} = 0.6*46*9.8 cos 29

F_{r}=236.57N

Since F_{r}>F, therefore, the block doesn’t slip and the frictional force acting is mgh=218.55N

Part 2.

Using the relationship that

Frictional force F_{s} = \mu_{s} mg cos \theta

mg sin \theta =\mu_{s} mg cos \theta

\mu_{s}= \frac {sin \theta}{cos \theta}

\mu_{s}= tan \theta

The maximum angle of inclination \theta = tan^{-1} \mu_{s}

\theta = tan^{-1} (0.6)

\theta= 30.96^{o}  

        

Part 3:

Net force on the object is given by

ma = mg sin 38 - \mu_{k} mg cos 38 where \mu_{k} is the coefficient of kinetic friction

 a = g ( sin 38 - \mu_{k} cos 38 )

                 = 9.8 ( sin 38 - (0.51) cos 38 )

                = 2.1m/s^{2}

7 0
4 years ago
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