Ask question

Ask question

All categories

3 years ago

6

A tsunami covers a distance of 500km in 83.3 minutes. If the period of vibration of the molecules is 35.0 minutes, what is the w

avelength of the wave?

1 answer:

marin [14]3 years ago

8 0

Answer:

210079.798 m

Explanation:

pls give brainliest :)

You might be interested in

At what vertical velocity should no object be launched at in order to achieve a height of 20m?

Free_Kalibri [48]

Answer:

19.8 m/s

Explanation:

Given:

Maximum vertical displacement of the object (H) = 20 m

Acceleration due to gravity (g) = 9.8 m/s²

At maximum height, the velocity of the object is 0 m/s for a moment. So, final velocity (v) at the maximum height is 0 m/s.

Now, let the initial velocity or velocity at launch be 'u' m/s.

Now, using the following equation of motion for vertical motion:

$v^2=u^2-2gH$

Rewriting in terms of 'u', we get:

$u^2=v^2+2gH\\\\u=\sqrt{v^2+2gH}$

Plug in the given values and solve for 'u'. This gives,

$u=\sqrt{0+2\times 9.8\times 20}\\\\u=\sqrt{392}\\\\u=19.8\ m/s$

Therefore, the vertical velocity at the launch is 19.8 m/s.

7 0

4 years ago

What does the narrator mean when he says that energy is “as old as time itsself “

guajiro [1.7K]

That as long as we know there has always been energy

Hope this helps :)

5 0

3 years ago

A long solenoid that has 1,140 turns uniformly distributed over a length of 0.415 m produces a magnetic field of magnitude 1.00

mezya [45]

Answer:

Therefore,

Current required is , I

$I = 0.0289\ Ampere$

Explanation:

Given:

Turns = N = 1140

length of solenoid = l = 0.415 m

Magnetic Field,

$B = 1.00\times 10^{-4}\ T$

To Find:

Current , I = ?

Solution:

If N is the number of turns in the length, the total current through the rectangle is NI. Therefore, Ampere’s law applied to this path gives

$\int {B} \, ds= Bl=\mu_{0}NI$

Where,

B = Strength of magnetic field

l = Length of solenoid

N = Number of turns

I = Current

$\mu_{0}=Permeability\ in\ free\ space=4\pi\times 10^{-7}\ Tm/A$

Therefore,

$I =\dfrac{Bl}{\mu_{0}N}$

Substituting the values we get

$I =\dfrac{1.00\times 10^{-4}\times 0.415}{4\times 3.14\times 10^{-7}\times 1140}=0.0289\ Ampere$

Therefore,

Current required is , I

$I = 0.0289\ Ampere$

3 0

4 years ago

A bicyclist steadily speeds up from rest to 6.00m/s in 7.30s.

Simora [160]

Answer:

21.899 m

Explanation:

The explanation here is a little differe because we are starting from rest. So, everyone does physics a little differently, but what I would start with is trying to find the accelaration. I've given the formula, now you are able to plug this into the displacement formula where you Velocity Initial = 0m/s (Since you are starting from rest) and V final = 6.00 m/s...

You just plug numbers into the formula after solving for accelaration and do some simple algebra! I hope this helps! I am attaching a new pdf for visuals! If you can't open it let me know! Also there is a star by accelaration because I didn't know if I spelled it right, sorry!

8 0

3 years ago

Car B is rounding the curve with a constant speed of 54 km/h, and car A is approaching car B in the intersection with a constant

levacccp [35]

This question is incomplete, the complete question is;

Car B is rounding the curve with a constant speed of 54 km/h, and car A is approaching car B in the intersection with a constant speed of 72 km/h. The x-y axes are attached to car B. The distance separating the two cars at the instant depicted is 40 m. Determine: the angular velocity of Bxy rotating frame (ω).

Answer:

the angular velocity of Bxy rotating frame (ω) is 0.15 rad/s

Explanation:

Given the data in the question and image below and as illustrated in the second image;

distance S = 40 m

V $_B$ = 54 km/hr

V $_A$ = 72 km/hr

α = 100 m

now, angular velocity of Bxy will be;

ω $_B$ = V $_B$ / α

so, we substitute

ω $_B$ = ( 54 × 1000/3600) / 100

ω $_B$ = 15 / 100

ω $_B$ = 0.15 rad/s

Therefore, the angular velocity of Bxy rotating frame (ω) is 0.15 rad/s

3 0

3 years ago