Which relation is a function? Question 3 options: {(1, 2); (1, 3); (1, 4); (1, 5)} {(1, 2); (2, 3); (3, 4); (4, 5)} {(1, 2); (3,
NeTakaya
To be a function for every identical x value it has to have a different Y value. If the set has two identical X values but they have different Y values it can't be a function.
The set that is a function is:
{(1, 2); (2, 3); (3, 4); (4, 5)}
Step-by-step explanation:
the max. value is when the smaller set (A) is completely contained in the larger set (B).
then n(A n B) is n(A) = 50.
the set intersection between A and B cannot get bigger than that. or A gets bigger ...
after all, the intersection means it is a set of all elements that exist in BOTH sets.
but then there must be other elements besides A and B in the universal set too, because n(universal set) = 96, and n(A u B) would be only 60.
the min. value could be the empty set or 0. but because n(universal set) = 96, and n(A) + n(B) = 110 and larger than 96, it means that there have to be some shared elements. at least 110 - 96 = 14 elements.
in this case there cannot be other elements in the universal set than A and B. and n(universal set) = n(AuB) = 96.
C = 2<span>πr
so
r = C/2</span><span>π
r = 3</span>π/2<span>π
r = 3/2
r = 1.5
A = </span><span>πr^2
A = </span><span>π(1.5)^2
A = 2.25</span><span>π
answer
</span><span>2.25π in²</span>
None of them? 6x3 is 18, 6x6x6 is 216, 6x6x6x6 is 1296, and 3x3x3x3x3x3 is 729
Eight and five hundred seventeen thousandths.
