Magnesium Phosphate is the answer
Answer:
I'm more then sure it is A but let my know it im wrong if i am sorry :)
Explanation:
Answer:

Explanation:
It is given that
B is the dominant allele which represents the black color
and b is the recessive allele which represents the white fur.
B being dominant will result into black color fur for genotype "Bb"
Given -
Frequency of black fur allele (p) is 
As per Hardy Weinberg's first law of equilibrium

Substituting the value of p in above equation, we get -

q represents the frequency for white fur allele
Frequency of white fur phenotype is

Frequency of homozygous black fur phenotype (BB) is

As per Hardy Weinberg's second law of equilibrium -

Combined frequency of homozygous and heterozygous black fur phenotype is
